Vector Mechanics for Engineers: Statics
Vector Mechanics for Engineers: Statics
12th Edition
ISBN: 9781259977268
Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek
Publisher: McGraw-Hill Education
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Chapter 7, Problem 7.154RP

Knowing that the turnbuckle has been tightened until the tension in wire AD is 850 N, determine the internal forces at the point indicated: 7.154 Point J.

Chapter 7, Problem 7.154RP, Knowing that the turnbuckle has been tightened until the tension in wire AD is 850 N, determine the

Expert Solution & Answer
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To determine

The internal forces.

Answer to Problem 7.154RP

The internal forces are V=400N, F=750N and the moment of force is 130Nm.

Explanation of Solution

The free body diagram is given in figure 1.

Vector Mechanics for Engineers: Statics, Chapter 7, Problem 7.154RP

From the diagram, net force along horizontal and vertical directions is zero. Write the equilibrium condition for the forces.

V=(CDAB(CDAB)2+BC2)TAD

F=(BC(CDAB)2+BC2)TAD

Here, TAD is the tension in wire AD, V is the internal force along horizontal direction and F is the force along vertical direction.

The net moment at point J is zero. Therefore, the equilibrium condition is,

M=V(BJ)+F(AB)

Here, M is the moment of internal force.

Conclusion:

Substitute 280 mm for CD, 120 mm for AB, 300 mm for BC and 850 N for TAD in the expression for V.

V=(280mm120mm(280mm120mm)2+(300mm)2)(850N)=400N

Substitute 280 mm for CD, 120 mm for AB, 300 mm for BC and 850 N for TAD in the expression for F.

F=(300mm(280mm120mm)2+(300mm)2)(850N)=750N

Substitute 400 N for V, 750 N for F, 100 mm for BJ and 120 mm for AB in the expression for M.

M=(400N)(100mm)+(750N)(120mm)=130000Nmm=130Nm

Therefore, the internal forces are V=400N, F=750N and the moment of force is 130Nm.

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Chapter 7 Solutions

Vector Mechanics for Engineers: Statics

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