Construction Materials, Methods and Techniques (MindTap Course List)
Construction Materials, Methods and Techniques (MindTap Course List)
4th Edition
ISBN: 9781305086272
Author: William P. Spence, Eva Kultermann
Publisher: Cengage Learning
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Chapter 7, Problem 6RQ

How does the addition of air-entraining materials to Portland cement improve the concrete?

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Problem 1: Given: In a given floor system, a 5-in concrete slab supported by T-beams of 24-ft spans, supporting 354 psf live load. The T-beams are spaced 2x4 ft on center, and bw (width of the beam web) = 15 inches. Total T-beam height is 25 inches. f'c = 4,000psi, fy = 60,000psi. Design the T-beam. Show all steps. Sketch your Design. Problem 2: Given: A 25"x25" column is subject to a factored axial load of Pu=1,200 kips, and factored design moment of Mu-354 kips-ft. f'c 4,000psi, fy = 60,000psi. Determine the required steel ratio (p) and ties. Sketch the design. 2.0 0.08 INTERACTION DIAGRAM R4-60.9 fc-4 ksi 1.8 1,- 60 ksi 0.07 Y=0.9 16 1.6 0.06 Kmax 0.05 1.4 f/f, = 0 0.04 00 K₁ = P₁/f'c Ag 1.2 12 0.03 0.25 1.0 10 0.02 0.01 0.8 0.6 0.4 €,= 0.0035 0.2 €,= 0.0050 0.0 h yh 0.50 0.75 1.0. 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 0.50 R₁ = P₁e/f'Agh
Given: In a given floor system, a 5-in concrete slab supported by T-beams of 24-ft spans, supporting 354 psf live load. The T-beams are spaced 2x4 ft on center, and bw (width of the beam web) = 15 inches. Total T-beam height is 25 inches. f'c = 4,000psi, fy = 60,000psi. Design the T-beam. Show all steps. Sketch your Design.
Problem 2: Given: A 25"x25" column is subject to a factored axial load of Pu=1,200 kips, and factored design moment of Mu-354 kips-ft. f'c 4,000psi, fy = 60,000psi. Determine the required steel ratio (p) and ties. Sketch the design. 2.0 P=0.08 INTERACTION DIAGRAM R4-60.9 fc-4 ksi 1.8 1,- 60 ksi 0.07 7=0.9 1.6 16 0.06 Kmax 0.05 1.4 f/f, = 0 0.04 90 K₁ = P₁/f'Ag 1.2 0.03 0.25 0.02 1.0 0.01 0.8 0.6 0.4 €= 0.0035 0.2 €,= 0.0050 0.0 h yh 0.50 0.75 1.0. 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 0.50 R₁ = P₁e/f'Ah
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