World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 7, Problem 48A
Interpretation Introduction

Interpretation:

A balanced chemical equation corresponding to the decomposition of hydrogen peroxide into oxygen and steam needs to be presented.

Concept Introduction:

  • A chemical reaction is expressed as a chemical equation having reactants and products on left and right side of the reaction arrow respectively.
  •   Reactants  Products

  • A balanced chemical equation is one in which the number of atoms of various elements on the reactants side is equal to that on the product side. It depicts the stoichiometry of a given reaction.
  • The equations are balanced in two steps:
  • 1) Balance the atoms by matching the number of atoms of each type on the reactants and product side.

    2) Adjust the coefficients to the smallest whole number. A coefficient of '1' is implied and therefore not explicitly written.

Expert Solution & Answer
Check Mark

Answer to Problem 48A

  2H2O2(aq)MnO2 2H2O (g) + O2(g)  

Explanation of Solution

The given equation involves the catalytic decomposition of hydrogen peroxide solution into oxygen gas and water vapour. The reactants and products are:

Reactant:

  Hydrogen peroxide, aqueous - H2O2(aq)

Products:

  Oxygen, gas - O2 (g)Water vapor - H2O (g)

Unbalanced equation:

  H2O2(aq)MnO2H2O (g) + O2(g)  

The above equation is not balanced since the number of O atoms is 2 on the reactants side and 3 on the products. In order to balance the above equation, multiply both H2O2 and H2O by 2 to get:

  2H2O2(aq)MnO2 2H2O (g) + O2(g)  

Conclusion

Therefore, 2 moles of hydrogen peroxide decomposes to form 2 moles of water vapour and 1 mole of oxygen gas.

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