Foundations of Astronomy (MindTap Course List)
14th Edition
ISBN: 9781337399920
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
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Chapter 7, Problem 23RQ
Could an object be orbiting another object and we only detect the radial motion via the Doppler effect?
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Why does the Doppler effect only find the radial velocity?
A distant galaxy is observed with a spectrometer. This galaxy produces an emission line that is identified as a Hydrogen transition that normally has a wavelength of 21 cm. For this galaxy, however, the emission line is observed at a wavelength of 33 cm. How fast is this galaxy moving away from us in units of km/s [round off your answer to 1 km/s]
A certain line in the spectrum of the light from a nebula has a wavelength of 656 nm instead of the 434 nm measured in the laboratory. If the nebula is movingr radially what is its speed relative to the Earth?
Chapter 7 Solutions
Foundations of Astronomy (MindTap Course List)
Ch. 7 - Prob. 1RQCh. 7 - Prob. 2RQCh. 7 - Prob. 3RQCh. 7 - Prob. 4RQCh. 7 - Prob. 5RQCh. 7 - Prob. 6RQCh. 7 - Prob. 7RQCh. 7 - Prob. 8RQCh. 7 - Prob. 9RQCh. 7 - Prob. 10RQ
Ch. 7 - Prob. 11RQCh. 7 - Prob. 12RQCh. 7 - Prob. 13RQCh. 7 - Prob. 14RQCh. 7 - Prob. 15RQCh. 7 - Prob. 16RQCh. 7 - How is heat different from temperature?Ch. 7 - Prob. 18RQCh. 7 - Prob. 19RQCh. 7 - Prob. 20RQCh. 7 - Prob. 21RQCh. 7 - Prob. 22RQCh. 7 - Could an object be orbiting another object and we...Ch. 7 - Prob. 24RQCh. 7 - How Do We Know? How is the macroscopic world you...Ch. 7 - Prob. 1PCh. 7 - Answer these questions for celestial bodies at...Ch. 7 - Prob. 3PCh. 7 - Prob. 4PCh. 7 - Prob. 5PCh. 7 - Prob. 6PCh. 7 - Prob. 7PCh. 7 - Prob. 8PCh. 7 - Prob. 9PCh. 7 - Prob. 10PCh. 7 - Prob. 11PCh. 7 - Prob. 12PCh. 7 - Prob. 1SOPCh. 7 - Prob. 2SOPCh. 7 - Prob. 1LTLCh. 7 - Prob. 2LTLCh. 7 - Prob. 3LTLCh. 7 - Prob. 4LTLCh. 7 - Prob. 5LTLCh. 7 - Prob. 6LTLCh. 7 - Prob. 7LTL
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- The nearest neutron star (a collated star made primarily of neutrons) is about 3.00 1018 m away from Earth. Given that the Milky Way galaxy (Fig. P1.81) is roughly a disk of diameter 1021 m and thickness 1019 m, estimate the number of neutron stars in the Milky Way to the nearest order of magnitude. Figure P1.81arrow_forwardSuppose the proper length of a UFO rocketship is 3475 kilometers, L. Then how fast is the rocketship moving relative to the Earth? Parameter value: L = 530 km Give the value of a = (c - v)/c. OB: OA: 9.999x10-3 1.170x10-2 OC: 1.369x10-2 OD: 1.602x10-2 but its length observed by a telescope on Earth is OE: OF: 1.874x10-2 2.192x10-2 OG: 2.565x10-2 OH: 3.001x10-2arrow_forwardIt can be shown that if an object orbiting a star of mass M in a circular orbit of radius R has speed v, then Rv? M Suppose a star orbits the center of the galaxy it is contained in with an orbit that is nearly circular with radius 18 R = 2.5 x 10 and velocity v = 230 km/s. Use the result above to estimate the mass of the portion of the galaxy inside the star's orbit (place all of this mass at the center of the orbit). Mass =arrow_forward
- (Astronomy) PSR1913+16 Problem III. As the shape of the graph shown is not skewed, the orbit can be assumed circular. Also assume the system is viewed edge-on (that is, the orbital system is not inclined to the observer). Using these assumptions, the maximum radial velocities, and the orbital period T = 7.75 hours, find the orbital radii of the stars from the center of mass. (Hints: The figures below may be helpful. Use v = 2πr/P, where v is velocity, P is period, and r is radius. Note: redshifts have positive radial velocities values in the upper figure, whereas blueshifts have negative radial velocity values.)arrow_forwardThe farthest objects in our Universe discovered by modern astronomers are so distant that light emitted by them takes billions of years to reach the Earth. These objects (known as quasars) have many puzzling features, which have not yet been satisfactorily explained. What is the distance in km of a quasar from which light takes 3.0 billion years to reach us ?arrow_forwardGiven the following equation for orbital velocity, 7=esin Of +/(1+ e cos 0) h h demonstrate mathematically that the magnitude of orbital velocity reaches its maximum at periapsis.arrow_forward
- How did Edwin Hubble use the concepts of the Doppler Effect to determine the speed/direction of celestial objects?arrow_forwardA star, which is 2.1 x 1020 m from the center of a galaxy, revolves around that center once every 2.8 x 108 years. Assuming each star in the galaxy has a mass equal to the Sun's mass of 2.0 x 1030 kg, the stars are distributed uniformly in a sphere about the galactic center, and the star of interest is at the edge of that sphere, estimate the number of stars in the galaxy.arrow_forwardDistances to the nearest stars (up to 500 ly away) can be measured by a technique called parallax, as shown . What are the angles θ1 and θ2 relative to the plane of the Earth’s orbit for a star 4.0 ly directly above the Sun?arrow_forward
- Can i have the answers to this table Thank you!arrow_forwardSuppose a star has the same mass as the Sun but has a diameter 5 times as large. Compare the total gravitational energy radiated away by the star with that radiated away by the Sun.arrow_forwardDouble stars are stars which are close enough and move slowly enough that they orbit each other. Each star is located at the focus of the ellipse of its orbit around the other star. Consider a binary star system which has an average angular separation of 6.1" arc and a period of 87.3 years. The annual parallax of the stars, p, is 0.192"arc. We call the measure of the angular separation of the two stars, . [remember that 1 degree is divided into 60 'arc (read this as 60 minutes of arc) and each 1'arc is subdivided into 60"arc (read this as 60 seconds of arc)]. The distance to the binarystar system is calculated from its parallax , p, of 0.192"arc, which has been measured carefully over a period of the last 92 years. First we must calculate the distance to the binary system: D = 1/p where p is the parallax in seconds of arc giving D in parsecs. The distance, D = 1/p = ________ pc How many light years does this correspond to? (remember that 1 pc = 3.26 lt yr) D (in light…arrow_forward
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