EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM
8th Edition
ISBN: 9780134554433
Author: CORWIN
Publisher: PEARSON CO
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Chapter 7, Problem 20E
Interpretation Introduction

(a)

Interpretation:

The chemical equation, Sn(s)+P(s)Sn3P2(s) is to be balanced by inspection.

Concept introduction:

A chemical reaction is a process in which rearrangement of atoms or ions takes place between two or more reacting species. A chemical equation is said to be balanced equation if the number of atoms of each elements on each side is same and all the reactants and products are written with their stoichiometric coefficient and physical states.

Expert Solution
Check Mark

Answer to Problem 20E

The balanced equation is 3Sn(s)+2P(s)Sn3P2(s).

Explanation of Solution

The unbalanced equation is expressed below.

Sn(s)+P(s)Sn3P2(s)

To write a balanced equation, it is necessary to count the number of atoms on each side. In the above equation, there are three tin atoms and two phosphorous atoms in the right side of reaction. Therefore, it is necessary to have three tin atoms and two phosphorous atoms on the left side of the reaction.

Therefore, the balanced equation is shown below.

3Sn(s)+2P(s)Sn3P2(s)

Conclusion

The balanced equation is 3Sn(s)+2P(s)Sn3P2(s).

Interpretation Introduction

(b)

Interpretation:

The chemical equation, Fe2(CO3)3(s)Fe2O3(s)+CO2(g) is to be balanced by inspection.

Concept introduction:

A chemical reaction is a process in which rearrangement of atoms or ions takes place between two or more reacting species. A chemical equation is said to be balanced equation if the number of atoms of each elements on each side is same and all the reactants and products are written with their stoichiometric coefficient and physical states.

Expert Solution
Check Mark

Answer to Problem 20E

The balanced chemical equation is Fe2(CO3)3(s)Fe2O3(s)+3CO2(g).

Explanation of Solution

The unbalanced equation is expressed below.

Fe2(CO3)3(s)Fe2O3(s)+CO2(g)

To write a balanced equation, it is necessary to count the number of atoms on each side. arrow. In the above equation, there are two iron atoms, three carbon atoms and nine oxygen atoms on the left side and there are two iron atoms, one carbon atom and five oxygen atoms on the right side. To balance the above chemical reaction, multiply the whole CO2 by 3 in given equation. Therefore, the balanced equation is shown below.

Fe2(CO3)3(s)Fe2O3(s)+3CO2(g)

Conclusion

The balanced chemical equation is Fe2(CO3)3(s)Fe2O3(s)+3CO2(g).

Interpretation Introduction

(c)

Interpretation:

The chemical equation, Fe(s)+Cd(NO3)2(aq)Fe(NO3)3(aq)+Cd(s) is to be balanced by inspection.

Concept introduction:

A chemical reaction is a process in which rearrangement of atoms or ions takes place between two or more reacting species. A chemical equation is said to be balanced equation if the number of atoms of each elements on each side is same and all the reactants and products are written with their stoichiometric coefficient and physical states.

Expert Solution
Check Mark

Answer to Problem 20E

The balanced chemical equation is given below. 2Fe(s)+3Cd(NO3)2(aq)2Fe(NO3)3(aq)+3Cd(s)

Explanation of Solution

The unbalanced equation is expressed below.

Fe(s)+Cd(NO3)2(aq)Fe(NO3)3(aq)+Cd(s)

To write a balanced equation, it is necessary to count the number of atoms on each side. In the above equation, iron and cadmium are balanced but nitrogen and oxygen are not balanced. To balance the above chemical reaction, multiply Fe(s) by 2, Cd(NO3)2(aq) by 3, Fe(NO3)3(aq) by 2 and Cd(s) by 3 in given equation. Therefore, the balanced equation is shown below.

2Fe(s)+3Cd(NO3)2(aq)2Fe(NO3)3(aq)+3Cd(s)

Conclusion

The balanced chemical equation is given below. 2Fe(s)+3Cd(NO3)2(aq)2Fe(NO3)3(aq)+3Cd(s)

Interpretation Introduction

(d)

Interpretation:

The chemical equation, Co(NO3)2(aq)+H2S(g)CoS(s)+HNO3(aq) is to be balanced by inspection.

Concept introduction:

A chemical reaction is a process in which rearrangement of atoms or ions takes place between two or more reacting species. A chemical equation is said to be balanced equation if the number of atoms of each elements on each side is same and all the reactants and products are written with their stoichiometric coefficient and physical states.

Expert Solution
Check Mark

Answer to Problem 20E

The balanced chemical reaction is shown below.

Co(NO3)2(aq)+H2S(g)CoS(s)+2HNO3(aq)

Explanation of Solution

The unbalanced equation is expressed below.

Co(NO3)2(aq)+H2S(g)CoS(s)+HNO3(aq)

To write a balanced equation, it is necessary to count the number of atoms on each side. In the above equation, cobalt and sulfur are balanced but nitrogen, hydrogen and oxygen are not balanced. To balance the above chemical reaction, multiply HNO3(aq) by 2 in given equation. Therefore, the balanced equation is shown below.

Co(NO3)2(aq)+H2S(g)CoS(s)+2HNO3(aq)

Conclusion

The balanced chemical reaction is shown below.

Co(NO3)2(aq)+H2S(g)CoS(s)+2HNO3(aq)

Interpretation Introduction

(e)

Interpretation:

The chemical equation, HClO4(aq)+Ba(OH)2(s)Ba(ClO4)2(s)+H2O(l) is to be balanced by inspection.

Concept introduction:

A chemical reaction is a process in which rearrangement of atoms or ions takes place between two or more reacting species. A chemical equation is said to be balanced equation if the number of atoms of each elements on each side is same and all the reactants and products are written with their stoichiometric coefficient and physical states.

Expert Solution
Check Mark

Answer to Problem 20E

The balanced chemical reaction is shown below.

2HClO4(aq)+Ba(OH)2(s)Ba(ClO4)2(s)+2H2O(l)

Explanation of Solution

The unbalanced equation is expressed below.

HClO4(aq)+Ba(OH)2(s)Ba(ClO4)2(s)+H2O(l)

To write a balanced equation, it is necessary to count the number of atoms on each side. In the above equation, barium is balanced but chlorine, hydrogen and oxygen are not balanced. To balance the above chemical reaction, multiply both HClO4(aq) and H2O(l) by 2 in given equation. Therefore, the balanced equation is shown below.

2HClO4(aq)+Ba(OH)2(s)Ba(ClO4)2(s)+2H2O(l)

Conclusion

The balanced chemical reaction is shown below.

2HClO4(aq)+Ba(OH)2(s)Ba(ClO4)2(s)+2H2O(l)

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Chapter 7 Solutions

EP INTRODUCTORY CHEM.-MOD.MASTERINGCHEM

Ch. 7 - Prob. 11CECh. 7 - Prob. 12CECh. 7 - Prob. 13CECh. 7 - Prob. 14CECh. 7 - Prob. 15CECh. 7 - Prob. 16CECh. 7 - Prob. 1KTCh. 7 - Prob. 2KTCh. 7 - Prob. 3KTCh. 7 - Prob. 4KTCh. 7 - Prob. 5KTCh. 7 - Prob. 6KTCh. 7 - Prob. 7KTCh. 7 - Prob. 8KTCh. 7 - Prob. 9KTCh. 7 - Prob. 10KTCh. 7 - Prob. 11KTCh. 7 - Prob. 12KTCh. 7 - Prob. 13KTCh. 7 - Prob. 14KTCh. 7 - Prob. 15KTCh. 7 - Prob. 16KTCh. 7 - Prob. 17KTCh. 7 - Prob. 18KTCh. 7 - Prob. 19KTCh. 7 - Prob. 20KTCh. 7 - Prob. 21KTCh. 7 - Prob. 22KTCh. 7 - Prob. 1ECh. 7 - Prob. 2ECh. 7 - Prob. 3ECh. 7 - Prob. 4ECh. 7 - Prob. 5ECh. 7 - Prob. 6ECh. 7 - Prob. 7ECh. 7 - Prob. 8ECh. 7 - Prob. 9ECh. 7 - Prob. 10ECh. 7 - Prob. 11ECh. 7 - Prob. 12ECh. 7 - Prob. 13ECh. 7 - Prob. 14ECh. 7 - Prob. 15ECh. 7 - Prob. 16ECh. 7 - Prob. 17ECh. 7 - Prob. 18ECh. 7 - Prob. 19ECh. 7 - Prob. 20ECh. 7 - Prob. 21ECh. 7 - Prob. 22ECh. 7 - Prob. 23ECh. 7 - Prob. 24ECh. 7 - Prob. 25ECh. 7 - Prob. 26ECh. 7 - Prob. 27ECh. 7 - Prob. 28ECh. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Prob. 31ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 34ECh. 7 - Prob. 35ECh. 7 - Prob. 36ECh. 7 - Prob. 37ECh. 7 - Prob. 38ECh. 7 - Prob. 39ECh. 7 - Prob. 40ECh. 7 - Prob. 41ECh. 7 - Prob. 42ECh. 7 - Prob. 43ECh. 7 - Prob. 44ECh. 7 - Prob. 45ECh. 7 - Prob. 46ECh. 7 - Prob. 47ECh. 7 - Prob. 48ECh. 7 - Prob. 49ECh. 7 - Prob. 50ECh. 7 - Prob. 51ECh. 7 - Prob. 52ECh. 7 - Prob. 53ECh. 7 - Prob. 54ECh. 7 - Prob. 55ECh. 7 - Prob. 56ECh. 7 - Prob. 57ECh. 7 - Prob. 58ECh. 7 - Prob. 59ECh. 7 - Prob. 60ECh. 7 - Prob. 61ECh. 7 - Prob. 62ECh. 7 - Prob. 63ECh. 7 - Prob. 64ECh. 7 - Prob. 65ECh. 7 - Prob. 66ECh. 7 - Prob. 67ECh. 7 - Prob. 68ECh. 7 - Prob. 69ECh. 7 - Prob. 70ECh. 7 - Prob. 71ECh. 7 - Prob. 72ECh. 7 - Prob. 73ECh. 7 - Prob. 74ECh. 7 - Prob. 75ECh. 7 - Prob. 76ECh. 7 - Prob. 77ECh. 7 - Prob. 78ECh. 7 - Prob. 79ECh. 7 - Prob. 80ECh. 7 - Prob. 81ECh. 7 - Prob. 82ECh. 7 - Prob. 83ECh. 7 - Prob. 84ECh. 7 - Prob. 85ECh. 7 - Prob. 86ECh. 7 - Prob. 87ECh. 7 - Prob. 88ECh. 7 - Prob. 1STCh. 7 - Prob. 2STCh. 7 - Prob. 3STCh. 7 - Prob. 4STCh. 7 - Prob. 5STCh. 7 - Prob. 6STCh. 7 - Prob. 7STCh. 7 - Prob. 8STCh. 7 - Prob. 9STCh. 7 - Prob. 10STCh. 7 - Prob. 11STCh. 7 - Prob. 12STCh. 7 - Prob. 13STCh. 7 - Prob. 14STCh. 7 - Prob. 15STCh. 7 - Prob. 16STCh. 7 - Prob. 17STCh. 7 - Prob. 18ST
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