Chapter 7, Problem 13MCQ

a.

To determine

Explain length of the bar $\text{'}\text{'}A\text{'}\text{'}$ is half the length of the base.

Answer to Problem 13MCQ

length of the bar is one half the length of the base.

Explanation of Solution

Given information:

A square was used as aframe to design the letter $\text{'}\text{'}A\text{'}\text{'}$ as shown below, the thickness of the major stroke of $\text{'}\text{'}A\text{'}\text{'}$ is $\frac{1}{12}$ the height.

  

Calculation:

The bar is along the diameter of the inscribed circle. It connects midpoints of each leg of the letter $\text{'}\text{'}A\text{'}\text{'}$ and it is parallel to base.

As per Triangle Mid segment theorem, a mid segment of a triangle is parallel to one side of the triangle, and its length is one half the length of that side.

Hence, length of the bar is one half the length of the base.

b.

To determine

Find the width of major stroke if length of letter $\text{'}\text{'}A\text{'}\text{'}$ is $3cm$ .

Answer to Problem 13MCQ

  $0.25cm$

Explanation of Solution

Given information:

A square was used as aframe to design the letter $\text{'}\text{'}A\text{'}\text{'}$ as shown below, the thickness of the major stroke of $\text{'}\text{'}A\text{'}\text{'}$ is $\frac{1}{12}$ the height.

  

Calculation:

Assume width of major stroke be,

  $\begin{array}{l}width=n\\ \frac{1}{12}=\frac{n}{3}\\ 3=12n\\ n=3/12\\ n=1/4\\ n=0.25cm\end{array}$

Hence, width of major stroke is, $0.25cm$ .