(a)
To find:The domain and range of the function
(a)
Answer to Problem 11CRT
The domain and range of the function
Explanation of Solution
Given information:
The function is
Graph:
The graph of the function
Figure(1)
Interpretation:
In the figure (1), the positive value yields a first quadrant angle and the negative value yields a second quadrant angle. Since the cosine function is positive in the first quadrant and negative in the second quadrant. So, the domain and range of the function
Therefore, the domain and range of the function
(b)
To find:The exact value of
(b)
Answer to Problem 11CRT
The exact value of
Explanation of Solution
Given information:
The expression is
Calculation:
Firstly find the value of
Substitute
Substitute
Substitute this value in the given expression.
Therefore, the exact value of
(c)
To represent:The expression
(c)
Answer to Problem 11CRT
The expression
Explanation of Solution
Given information:
The expression is
Calculation:
Take
The value of adjacent is
Use the formula for tangent.
As
Substitute
Therefore, the expression
Chapter 7 Solutions
Precalculus: Mathematics for Calculus - 6th Edition
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning