Explanation Before drilling, the center of mass of the disk is ( x CM , y CM ) = ( 0 , 0 ) . As the metal disk has uniform thickness, the mass is proportional to the area. m S m L = A S A L Here, m S is the mass of the small circle, m L is the mass of the large circle, A S is the area of the small circle and A L is the area of the large circle. Find the equation for the x coordinate of the center of mass of the disk after the hole has been drilled. x CM = m L x L + m S x S m L + m S = 0 x L = − m S m L x S = − A S A L x S = − π r S 2 π r L 2 − π r S 2 x S = − r S 2 r L 2 − r S 2 x S (I) Here, x CM is the x coordinate of the centre of mass, x L is the x coordinate of the centre of mass of the large circle, x S is the x coordinate of the centre of mass of the small circle, r L is the radius of the large circle and r S is the radius of the small circle

3rd Edition

ISBN: 9780073512150

Author: Alan Giambattista, Betty Richardson, Robert C. Richardson Dr.

Publisher: McGraw-Hill Education

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Chapter 7, Problem 100P

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The centre of mass of the disk after the hole has been drilled.

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Chapter 7, Problem 99P

Chapter 7, Problem 101P

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