PRIN.OF OPERATIONS MANAGEMENT-MYOMLAB
PRIN.OF OPERATIONS MANAGEMENT-MYOMLAB
11th Edition
ISBN: 9780135226742
Author: HEIZER
Publisher: PEARSON
bartleby

Concept explainers

Question
Book Icon
Chapter 6.S, Problem 20P

a)

Summary Introduction

To establish: Upper and lower control limits for the control chart and graph the data.

Introduction: Control charts used to determine whether the process is under control or not. Attributes and variables are the factors under the control charts.

a)

Expert Solution
Check Mark

Answer to Problem 20P

The upper control limit is 0.05812 and lower control limit is 0.

Explanation of Solution

Given information:

The following information is given:

Sample 1 2 3 4 5 6 7 8 9 10
Defectives 5 7 4 4 6 3 5 6 2 8

Compute the defective rate (p¯) :

Defective rate is calculated by dividing the sum of defectives and multiple of number of samples and sample size. Hence, the defective rate is 0.025.

p¯=Sum of defectivesNumber of samples×Sample size=5+7+4+4+6+3+5+6+2+810×200=502,000=0.025

Determine (σp¯) standard deviation of the sampling distribution:

Sample size is given as 200 and the defective rate is calculated as 0.025. Substitute the values in above equation. Hence, the standard deviation is 0.01104.

σp=p¯×(1p¯)n=0.025×(10.025)200=0.025×0.975200=0.01104

Determine UCL:

It can be calculated by adding the defective rate with the value attained by multiplying the number of standard deviation for setting the limit and standard deviation of the sampling distribution.

UCLp=p¯+z×σp=0.025+3×0.01104=0.05812

Hence, the UCL value is 0.05812.

Determine LCL:

It can be calculated by subtracting the defective rate with the value attained by multiplying the number of standard deviation for setting the limit and standard deviation of the sampling distribution.

LCLp=p¯z×σp=0.0253×0.01104=0.00812=0

Hence, the LCL value is 0.

Draw a p-chart for the attained values:

PRIN.OF OPERATIONS MANAGEMENT-MYOMLAB, Chapter 6.S, Problem 20P , additional homework tip  1

b)

Summary Introduction

To determine: Whether the process been in control.

Introduction: Control charts used to determine whether the process is under control or not. Attributes and variables are the factors under the control charts.

b)

Expert Solution
Check Mark

Answer to Problem 20P

The process been in control.

Explanation of Solution

Given information:

The following information is given:

Sample 1 2 3 4 5 6 7 8 9 10
Defectives 5 7 4 4 6 3 5 6 2 8

Determine whether the process in control:

Since all the values are within the upper and lower control limits, the process seems to be in control.

The last two samples, sample number #9 and sample number #10 are showing a wider dispersion from the center line. Further samples need to be drawn and verified whether the defective rates increase in dispersion.

c)

Summary Introduction

To establish: Upper and lower control limits for the control chart and graph the data, if the sample size were 100.

Introduction: Control charts used to determine whether the process is under control or not. Attributes and variables are the factors under the control charts.

c)

Expert Solution
Check Mark

Answer to Problem 20P

The upper control limit is 0.11537 and lower control limit is 0.

Explanation of Solution

Given information:

The following information is given:

Sample 1 2 3 4 5 6 7 8 9 10
Defectives 5 7 4 4 6 3 5 6 2 8

Compute the defective rate (p¯) :

Defective rate is calculated by dividing the sum of defectives and multiple of number of samples and sample size. Hence, the defective rate is 0.05.

p¯=Sum of defectivesNumber of samples×Sample size=5+7+4+4+6+3+5+6+2+810×100=501,000=0.05

Determine (σp¯) standard deviation of the sampling distribution:

Sample size is given as 100 and the defective rate is calculated as 0.05. Substitute the values in above equation. Hence, the standard deviation is 0.02179.

σp=p¯×(1p¯)n=0.05×(10.05)100=0.05×0.95100=0.02179

Determine UCL:

It can be calculated by adding the defective rate with the value attained by multiplying the number of standard deviation for setting the limit and standard deviation of the sampling distribution.

UCLp=p¯+z×σp=0.05+3×0.02179=0.11537

Hence, the UCL value is 0.11537.

Determine LCL:

It can be calculated by subtracting the defective rate with the value attained by multiplying the number of standard deviation for setting the limit and standard deviation of the sampling distribution.

LCLp=p¯z×σp=0.053×0.02179=0.01537=0

Hence, the LCL value is 0.

Draw a p-chart for the attained values:

PRIN.OF OPERATIONS MANAGEMENT-MYOMLAB, Chapter 6.S, Problem 20P , additional homework tip  2

Since all the values are within the upper and lower control limits, the process seems to be in control. This is expected, as the observations were within the limits even when the limits were narrower.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Explain how to contruct process control chart and use them to determine whether a process is out of statistical control.
Why is it important to prove that a process is proven capable before developing statistical control limits (i.e., SPC charts)?
What is it important to prove that a process is proven capable before developing statistical control limit ?

Chapter 6 Solutions

PRIN.OF OPERATIONS MANAGEMENT-MYOMLAB

Ch. 6.S - Prob. 11DQCh. 6.S - Prob. 12DQCh. 6.S - Prob. 13DQCh. 6.S - Prob. 14DQCh. 6.S - Prob. 15DQCh. 6.S - Prob. 16DQCh. 6.S - Prob. 17DQCh. 6.S - Prob. 18DQCh. 6.S - Prob. 19DQCh. 6.S - Prob. 1PCh. 6.S - Prob. 2PCh. 6.S - Prob. 3PCh. 6.S - Prob. 4PCh. 6.S - Prob. 5PCh. 6.S - Prob. 6PCh. 6.S - Prob. 7PCh. 6.S - Prob. 8PCh. 6.S - Prob. 9PCh. 6.S - Prob. 10PCh. 6.S - Prob. 11PCh. 6.S - Prob. 12PCh. 6.S - Prob. 13PCh. 6.S - Prob. 14PCh. 6.S - Prob. 15PCh. 6.S - Prob. 16PCh. 6.S - Prob. 17PCh. 6.S - Prob. 18PCh. 6.S - Prob. 19PCh. 6.S - Prob. 20PCh. 6.S - Prob. 21PCh. 6.S - Prob. 22PCh. 6.S - Prob. 23PCh. 6.S - Prob. 24PCh. 6.S - Prob. 25PCh. 6.S - Prob. 28PCh. 6.S - Prob. 29PCh. 6.S - Prob. 30PCh. 6.S - Prob. 32PCh. 6.S - Prob. 33PCh. 6.S - Prob. 34PCh. 6.S - Prob. 35PCh. 6.S - Prob. 36PCh. 6.S - Prob. 37PCh. 6.S - Prob. 39PCh. 6.S - Prob. 40PCh. 6.S - Prob. 41PCh. 6.S - Prob. 42PCh. 6.S - Prob. 43PCh. 6.S - Prob. 44PCh. 6.S - Prob. 45PCh. 6.S - Prob. 46PCh. 6.S - Prob. 48PCh. 6.S - Prob. 49PCh. 6.S - Prob. 50PCh. 6.S - Prob. 51PCh. 6.S - Prob. 52PCh. 6.S - Prob. 53PCh. 6.S - Prob. 54PCh. 6.S - Prob. 55PCh. 6.S - Prob. 1CSCh. 6.S - Prob. 2CSCh. 6.S - Prob. 1.1VCCh. 6.S - Prob. 1.2VCCh. 6.S - Prob. 1.3VCCh. 6.S - Prob. 2.1VCCh. 6.S - Prob. 2.2VCCh. 6.S - Prob. 2.3VCCh. 6.S - Prob. 2.4VCCh. 6 - Prob. 1EDCh. 6 - Prob. 1DQCh. 6 - Prob. 2DQCh. 6 - Prob. 3DQCh. 6 - Prob. 4DQCh. 6 - Prob. 5DQCh. 6 - Prob. 6DQCh. 6 - Prob. 7DQCh. 6 - Prob. 8DQCh. 6 - Prob. 9DQCh. 6 - Prob. 10DQCh. 6 - Prob. 11DQCh. 6 - Prob. 12DQCh. 6 - Prob. 13DQCh. 6 - Prob. 14DQCh. 6 - Prob. 15DQCh. 6 - Prob. 16DQCh. 6 - Prob. 17DQCh. 6 - Prob. 18DQCh. 6 - An avant-garde clothing manufacturer runs a series...Ch. 6 - Prob. 2PCh. 6 - Prob. 3PCh. 6 - Prob. 4PCh. 6 - Kathleen McFaddens restaurant in Boston has...Ch. 6 - Prob. 6PCh. 6 - Prob. 7PCh. 6 - Prob. 8PCh. 6 - Prob. 9PCh. 6 - Prob. 10PCh. 6 - Prob. 11PCh. 6 - Prob. 12PCh. 6 - Prob. 13PCh. 6 - Prob. 14PCh. 6 - Prob. 15PCh. 6 - Prob. 16PCh. 6 - Prob. 17PCh. 6 - Prob. 18PCh. 6 - Prob. 19PCh. 6 - Prob. 20PCh. 6 - Prob. 21PCh. 6 - Prob. 1CSCh. 6 - Prob. 2CSCh. 6 - Prob. 3CSCh. 6 - Prob. 1.1VCCh. 6 - Prob. 1.2VCCh. 6 - Prob. 1.3VCCh. 6 - Prob. 1.4VCCh. 6 - Prob. 2.1VCCh. 6 - Prob. 2.2VCCh. 6 - Prob. 2.3VCCh. 6 - Prob. 2.4VCCh. 6 - Prob. 3.1VCCh. 6 - Prob. 3.2VCCh. 6 - Prob. 3.3VCCh. 6 - Prob. 3.4VCCh. 6 - Prob. 3.5VC
Knowledge Booster
Background pattern image
Operations Management
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, operations-management and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Practical Management Science
Operations Management
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:Cengage,
Text book image
Operations Management
Operations Management
ISBN:9781259667473
Author:William J Stevenson
Publisher:McGraw-Hill Education
Text book image
Operations and Supply Chain Management (Mcgraw-hi...
Operations Management
ISBN:9781259666100
Author:F. Robert Jacobs, Richard B Chase
Publisher:McGraw-Hill Education
Text book image
Business in Action
Operations Management
ISBN:9780135198100
Author:BOVEE
Publisher:PEARSON CO
Text book image
Purchasing and Supply Chain Management
Operations Management
ISBN:9781285869681
Author:Robert M. Monczka, Robert B. Handfield, Larry C. Giunipero, James L. Patterson
Publisher:Cengage Learning
Text book image
Production and Operations Analysis, Seventh Editi...
Operations Management
ISBN:9781478623069
Author:Steven Nahmias, Tava Lennon Olsen
Publisher:Waveland Press, Inc.