Chapter 6.4, Problem 75E

(a)

To determine

To Find:The work done in terms of the distance $d$

Answer to Problem 75E

The work done in terms of the distance $d=216.506d$

Explanation of Solution

Given information: One competitor drags the block with a constant force of $250pounds$ at a constant angle of ${30}^{\circ }$ with the horizontal

Concept used:The work W done by a constant force $F$ as its point of application moved along the vector $\overrightarrow{PQ}$ is following

  $W=F.\overrightarrow{PQ}$

Calculation:

constant force of $250pounds$ at a constant angle of ${30}^{\circ }$ with the horizontal

The work $W$ done by a constant force $F$ as its point of application moved along the vector $\overline{PQ}$ is following

  $\begin{array}{l}W=F.\overrightarrow{PQ}\\ W=250\times d\times \cos {30}^{\circ }\\ W=250\times d\times \frac{\sqrt{3}}{2}\end{array}$

(b)

To determine

complete the given table

Answer to Problem 75E

d(in feet)	25	50	100
work	5412.65	21650.6	43301.2

Explanation of Solution

Given information:

The work done in terms of the distance $d=216.506d$

Calculation:

d(in feet)	25	50	100
work	5412.65	21650.6	43301.2