Chapter 6.4, Problem 43PP

Interpretation Introduction

Interpretation:

We are asked to write the formula for polyatomic ions and name each of the given compounds.

Concept Introduction:

The ionic compound is formed when the cation and anion come together. Ionic compound is formed by crisscross method. In this method the numerical value of ionic charges on cation and anion interchanged to become the subscript of the other ion.

To name the ionic compound first we name the cation that is name of the element followed by name of the anion. Consider an example $\text{NaCl}$ . Here ${\text{Na}}^{+1}$ is cation and ${\text{Cl}}^{-1}$ is anion, so the compound is named with Sodium followed by name of the anion that is chloride ion. Therefore the name of the $\text{NaCl}$ compound is ‘sodium chloride’.

To Determine:

The name each of the following compounds:

1. ${\text{Na}}_{\text{2}}{\text{CO}}_{\text{3}}$
2. ${\left({\text{NH}}_{\text{4}}\right)}_{\text{2}}\text{S}$
3. ${\text{Ba}}_{\text{3}}{{\text{(PO}}_{\text{4}}\text{)}}_{\text{2}}$
4. ${\text{Sn(NO}}_{\text{2}}{\text{)}}_{\text{2}}$