Chapter 6.3, Problem 52STP

To determine

To find: the samemetric approximation.

Answer to Problem 52STP

The same metric approximation is $H$ .

Explanation of Solution

Given information:

A piece of notebook paper measures $8\frac{1}{2}$ inches by 11 inches.

F: 2m by 2.8 m

G: 3 cm by 4 cm

H: 22 cm by 28 cm

J: 30 cm by 40 m.

Calculation:

Dimensions of notebook are $8\frac{1}{2}\text{in}\times \text{11}\text{in}$ .

Use the below conversions,

  $\begin{array}{c}1\text{in=2}\text{.54}\text{cm=0}\text{.0254}\text{m}\text{.}\\ \text{8}\frac{1}{2}\text{in}\text{.=}8\frac{1}{2}\times 2.54\text{cm}\\ \approx \text{22}\text{cm}\\ \text{11}\text{in}\text{.=11}\times \text{2}\text{.54}\text{cm}\\ \approx \text{28}\text{cm}\end{array}$

Equivalent dimensions are $22\text{cm}\times \text{28}\text{cm}\text{.}$

Hence, the same metric approximation is $H$ .