Explanation Calculation: Consider the provided position equation, s = 1 2 a t 2 + v 0 t + s 0 Find the equations by substituting different values of s at different times. For s = 132 at t = 1 , substitute 132 for s and 1 for t in the position equation, 1 2 a 1 2 + v 0 1 + s 0 = 132 1 2 a + v 0 + s 0 = 132 a + 2 v 0 + 2 s 0 2 = 132 a + 2 v 0 + 2 s 0 = 264 …… (1) For s = 100 at t = 2 , substitute 100 for s and 2 for t in the position equation, 1 2 a 2 2 + v 0 2 + s 0 = 100 1 2 a 4 + 2 v 0 + s 0 = 100 2 a + 2 v 0 + s 0 = 100 …… (2) For s = 36 at t = 3 , substitute 36 for s and 3 for t in the position equation, 1 2 a 3 2 + v 0 3 + s 0 = 36 9 2 a + 3 v 0 + s 0 = 36 9 a + 6 v 0 + 2 s 0 2 = 36 9 a + 6 v 0 + 2 s 0 = 72 …… (3) Convert the system of equations to row echelon form by performing the below steps. Multiply both sides of equation (1) by − 2 , − 2 a + 2 v 0 + 2 s 0 = − 2 264 − 2 a − 4 v 0 − 4 s 0 = − 528 …… (4) Add equations (4) and (2), − 2 a − 4 v 0 − 4 s 0 = − 528 2 a + 2 v 0 + s 0 = 100 ¯ − 2 v 0 − 3 s 0 = − 428 …… (5) Multiply both sides of equation (1) by − 9 , − 9 a + 2 v 0 + 2 s 0 = − 9 264 − 9 a

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ISBN: 9781337282291

Author: Ron Larson

Publisher: Cengage Learning

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Chapter 6.3, Problem 46E

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To calculate: The position equation, s=12at2+v0t+s0, for an object, where s=132 at t=1, s=100 at t=2 and s=36 at t=3.

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Chapter 6.3, Problem 45E

Chapter 6.3, Problem 47E

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The position equation, s = 1 2 a t 2 + v 0 t + s 0 , for an object, where s = 132 at t = 1 , s = 100 at t = 2 and s = 36 at t = 3 .

Solution Summary: The author calculates the position equation by substituting different values of s at different times.

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To calculate: The position equation, s=12at2+v0t+s0, for an object, where s=132 at t=1, s=100 at t=2 and s=36 at t=3.

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Chapter 6 Solutions