Chapter 6.3, Problem 33PPS

To determine

To order: Following groups of rate from least to greatest.

(i) 500 meter/hour (ii) 7 yd/min (iii) 6 inches/ second

Answer to Problem 33PPS

Order of rates from least to greatest is:

7 yd/min, 500 meter/hour, , 6 inches/ second

Explanation of Solution

Given information: Following three rates are given:

(i) 500 meter/hour (ii) 7 yd/min (iii) 6 inches/ second

Formula used:

First, all the different units given will be converted in oz (ounce) only, using following conversion formulae:

  $\begin{array}{l}\left(\text{i}\right)1\text{ meter }=39.37\text{ inches }\left(\text{ii}\right)\text{ 1 yard }=36\text{ inches }\\ \left(\text{iii}\right)\text{ 1 hour }=3600\text{ seconds }\left(\text{iv}\right)\text{ 1 minute }=60\text{ seconds}\end{array}$

Calculation:

Using conversion formulae,

  $500\text{meter/hour}=\frac{500\times 39.37}{3600}=\frac{19685}{3600}=5.486$ Inches/second

And

  $7\text{yd/min }=\frac{7\times 36}{60}=\frac{42}{10}=4.2$ Inches/ second

So, all given rates in same units are

(i) 5.486 inches/sec (ii) 4.2 inches/sec (iii) 6 inches/sec

Therefore, all given rates from least to greatest is ordered as:

4.2 inches/sec, 5.486 inches/sec, 6 inches/sec or, 7 yd/min, 500 meter/hour, 6 inches/ second