Chapter 6.3, Problem 26IP

a.

To determine

Calculate the percent of the Great Lakes covered by Lake Erie.

Answer to Problem 26IP

The percentage of area covered is $10.5\%$ .

Explanation of Solution

Given: It is given in the question that area of Erie is $9922$ and the total area is $94267$ .

Concept Used:

In this, use the concept of percent equation and the equation is $Part=Percent\cdot Whole$ .

Calculation:

The total area of the Great Lakes is $7320+9922+22316+23011+31698=94267sq.mi.$

In this, the part and the whole are given, looking for a part. Let p represent part.

  $\begin{array}{l}Part=Percent\cdot Whole\\ 9922=p\cdot 64267\\ p=\frac{9922}{64267}\\ p=0.105\\ p=0.105\times 100\\ p=10.5\%\end{array}$

Conclusion:

The percentage is $10.5\%$ .

b.

To determine

Calculate the percent of the Great Lakes covered by Lake Hurion.

Answer to Problem 26IP

The percentage of area covered is $24.4\%$ .

Explanation of Solution

Given:

It is given in the question that area of Huron is $23011$ and the total area is $94267$ .

Concept Used:

In this, use the concept of percent equation and the equation is $Part=Percent\cdot Whole$ .

Calculation: The total area of the Great Lakes is $7320+9922+22316+23011+31698=94267sq.mi.$

In this, the part and the whole are given, looking for a part. Let p represent part.

  $\begin{array}{l}Part=Percent\cdot Whole\\ 23011=p\cdot 94267\\ p=\frac{23011}{94267}\\ p=0.244\\ p=0.244\times 100\\ p=24.4\%\end{array}$

Conclusion:

The area covered is $24.4\%$ .

c.

To determine

Calculate the new area of the Michigan.

Answer to Problem 26IP

The new area of the Michigan are $20530$

Explanation of Solution

Given: It is given in the question that the area of the Lake Michigan is $22316$ and the area is decreased by $8\%$ .

Concept Used:

In this, use the concept of percent equation and the equation is $Part=Percent\cdot Whole$ .

Calculation: If the area was decreased by $8\%$ , it is now $92\%$ .

In this, the part and the whole are given, looking for a part. Let t represent part.

  $\begin{array}{l}Part=Percent\cdot Whole\\ t=92\%\cdot 22316\\ t=0.92\cdot 22316\\ t=20530.72\approx 20530\end{array}$

Conclusion:

The new area is $20530$ .