Chapter 6.3, Problem 14E

To determine

To calculate: The value of the trigonometric function $\cos \left(-60\right)°$ .

Answer to Problem 14E

The value of the trigonometric function $\cos \left(-60\right)°$ is $\frac{1}{2}$ .

Explanation of Solution

Given information:

The trigonometric function $\cos \left(-60\right)°$ .

Formula used:

Coordinate plane is divided into four quadrants.

In the first quadrant all trigonometric functions that is $\sin \theta ,cos\theta ,\tan \theta ,\csc \theta ,\sec \theta \text{ and }\cot \theta$ are positive.

In the second quadrant only sine and cosecant trigonometric functions that is $\sin \theta \text{ and }\csc \theta$ are positive and remaining $cos\theta ,\tan \theta ,\sec \theta \text{ and }\cot \theta$ are negative.

In the third quadrant only tangent and cotangent trigonometric functions that is $\tan \theta \text{ and }\cot \theta$ are positive and remaining $cos\theta ,sin\theta ,\sec \theta \text{ and }\csc \theta$ are negative.

In the fourth quadrant only cosine and secant trigonometric functions that is $\cos \theta \text{ and }\sec \theta$ are positive and remaining $\sin \theta ,\tan \theta ,\csc \theta \text{ and }\cot \theta$ are negative.

The reference angle $\overline{\theta }$ is the angle associated with the angle $\theta$ in the standard position. It is the acute angle that is formed by the terminal side of $\theta$ and the x -axis.

Calculation:

Consider the provided trigonometric function $\cos \left(-60\right)°$ .

Denote $\theta =\left(-60\right)°$ .

First estimate the reference angle $\overline{\theta }$ associated with the angle $\theta$ .

From the figure provided below,

  

The provided angle has terminal side in Quadrant $\text{IV}$ .

The reference angle is,

  $\overline{\theta }=60°$

Recall that coordinate plane is divided into four quadrants.

In the fourth quadrant only cosine and secant trigonometric functions that is $\cos \theta \text{ and }\sec \theta$ are positive and remaining $\sin \theta ,\tan \theta ,\csc \theta \text{ and }\cot \theta$ are negative.

So, cosine trigonometric function, $\cos \left(-60\right)°$ is positive.

Therefore,

  $\begin{array}{c}\cos \left(-60\right)°=\cos 60°\\ =\frac{1}{2}\end{array}$

Thus, the value of the trigonometric function $\cos \left(-60\right)°$ is $\frac{1}{2}$ .