The values of f x ( 0 , y ) by calculating the limit lim h → 0 ( f ( h , y ) − f ( 0 , y ) h ) where function f is defined as f ( x , y ) = { x y ( x 2 − y 2 ) x 2 + y 2 , for ( x , y ) ≠ ( 0 , 0 ) 0 , for ( x , y ) = ( 0 , 0 ) .
The values of f x ( 0 , y ) by calculating the limit lim h → 0 ( f ( h , y ) − f ( 0 , y ) h ) where function f is defined as f ( x , y ) = { x y ( x 2 − y 2 ) x 2 + y 2 , for ( x , y ) ≠ ( 0 , 0 ) 0 , for ( x , y ) = ( 0 , 0 ) .
Solution Summary: The author calculates the value of function f_x(0,y) by calculating the limit.
To calculate: The values of fx(0,y) by calculating the limit limh→0(f(h,y)−f(0,y)h) where function f is defined as f(x,y)={xy(x2−y2)x2+y2,for (x,y)≠(0,0)0 , for (x,y)=(0,0).
(b)
To determine
To calculate: The values of fy(x,0) by calculating the limit limh→0(f(x,h)−f(x,0)h) where function f is defined as f(x,y)={xy(x2−y2)x2+y2,for (x,y)≠(0,0)0 , for (x,y)=(0,0).
(c)
To determine
To calculate: The values of the function fyx(0,0) and fxy(0,0) where function f is defined as f(x,y)={xy(x2−y2)x2+y2,for (x,y)≠(0,0)0 , for (x,y)=(0,0) and also compare fyx(0,0) and fxy(0,0) for given function.
University Calculus: Early Transcendentals (4th Edition)
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