The analysis of this section applies also to linear polyatomic molecules, for which no rotation about the axis of symmetry is possible. An example is
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- To obtain a more clearly defined picture of the FermiDirac distribution, consider a system of 20 FermiDirac particles sharing 94 units of energy. By drawing diagrams like Figure P10.11, show that there are nine different microstates. Using Equation 10.2, calculate and plot the average number of particles in each energy level from 0 to 14E. Locate the Fermi energy at 0 K on your plot from the fact that electrons at 0 K fill all the levels consecutively up to the Fermi energy. (At 0 K the system no longer has 94 units of energy, but has the minimum amount of 90E.) 1 Microstate8 others? One of the nine equally probable microstates for 20 FD particles with a total energy of 94E.arrow_forwardThe vibrational frequency n for Br2 is 323 cm-1 and the energy difference between its two lowest rotational energy levels, J = 0 and J = 1, is 0.164 cm-1. Calculate the relative populations of the v = 1 and v = 0 vibrational energylevels and the relative populations of the two lowest rotational energy levels for Br2 at 300 K. Comment on your results.arrow_forwardFor an O2 molecule, the constant E is approximately 0.00018 eV. Estimate the rotational partition function for an O2 molecule at room temperature.arrow_forward
- The characteristic rotational energy for a diatomic molecule consisting of two idential atoms of mass 14 u (unified mass units) is 3.68 e-4 eV. Calculate the separation distance between the two atoms. Subarrow_forward(a): Calculate Miller's indices in the hexagonal structure of its intersections. ai = 1, ar--1/2, as = 1,c= o and draw it. (b): the potential energy of a diatomic molecule is given by U = A B . where A and B are constants and r is the separation distance between the atoms. For the H2 molecule, take A = 0.124 x 10-120 eV. m2 and B = 1.488 x 10 eV.m. Find the separation distance at which the energy of the molecule is a minimum. Q3: Calculate the dhai of tetragonal using the concepts of reciprocal latticearrow_forwardIn solid KCI the smallest distance between the centers of a. potassium ion and a chloride ion is 314 pm. Calculate the length of the edge of the unit cell and the density of KCI, assuming it has the same structure as sodium chloride.arrow_forward
- The equipartition theorem is valid only if kT is very much greater than the separation between energy levels of the mode of motion, Δε. Translational and rotational energy levels are sufficiently close together that this is true for most molecules at room temperature. However, the separation between vibrational energy levels is much greater, such that the equipartition theorem may be used to calculate the total contribution to the internal energy from all modes of motion only at high temperatures. The exact expression for the average contribution to the energy from vibration isgiven by Δε{1 - e-Δε/kT}. (a) For chlorine, Cl2, the separation between vibrational energy levels is 6.70 kJ mol-1. Estimate the temperature at which the equipartition theorem becomes valid. (b) An exponential function may be expanded as ex = 1 + x + (1)/(2)x2 + ... if x < 1. Show that in th is case, the exact expression reduces to the result obtained from the equipartition theorem.arrow_forwardEstimate kBT at room temperature, and convert this energy into electronvolts (eV). Using this result, answer the following: (a) Would you expect hydrogen atoms to be ionized at room temperature? (The binding energy of an electron in a hydrogen atom is 13.6 eV.) (b) Would you expect the rotational energy levels of diatomic molecules to be excited at room temperature? (It costs about 10−4 eV to promote such a system to an excited rotational energy level.)arrow_forwardThe greenhouse-gas carbon dioxide molecule CO2 strongly absorbs infrared radiation when its vibrational normal modes are excited by light at the normal-mode frequencies. CO₂ is a linear triatomic molecule, as shown in (Figure 1), with oxygen atoms of mass mo bonded to a central carbon atom of mass mc. You know from chemistry that the atomic masses of carbon and oxygen are, respectively, 12 and 16. Assume that the bond is an ideal spring with spring constant k There are two normal modes of this system for which oscillations take place along the axis. (You can ignore additional bending modes.) In this problem, you will find the normal modes and then use experimental data to determine the bond spring constant. Figure O 1 mo T X₁ k C 2 mc 1X₂ k 1 of 1 > O 3 mo 1 X3 Part A Let ₁, 2, and 3 be the atoms' positions measured from their equilibrium positions. First, use Hooke's law to write the net force on each atom. Pay close attention to signs! For each oxygen, the net force equals mod²x/dt².…arrow_forward
- Consider a molecule that can be in one of two different conformation states A or B. These states are two different arrangements of the atoms: e.g., in state B, one part of the molecule could be rotated about a bond with respect to the rest of the molecule. Assume the energies of states A and B are 4e-21 and 8e-21 J respectively. At room temperature, T = 298 K, what is the relative likelihood of the molecule being found in state B vs state A? 37.8 Submit Answer Incorrect. Tries 2/3 Previous Tries If the temperature decreases by 25 K to T = 273 K, what is the relative likelihood of the molecule being found in state B vs state A? 34.58 Submit Answer Incorrect. Tries 1/3 Previous Tries If the temperature increases by 100 K to T = 398 K, what is the relative likelihood of the molecule being found in state B vs state A? Submit Answer Tries 0/3arrow_forwardThe equilibrium number of vacancies for silver at 800 °C is 3.6 x 1023 vacancies per cubic meter. The atomic mass and density for silver at this temperature are 107.9 g/mol and 9.5 g/cm3 respectively. Calculate the energy for vacancy formation in silver at 800 °C. Given the: Avogadro Number, NA= 6.023 x 1023 atoms/mol Boltzman constant, kB = 8.62 x 10-5 eV/Karrow_forwardSet up the relevant equations with estimates of all missing parameters. The molecular bond (spring constant) of HCl is about 470 N/m. The moment of incrtia is 2.3 x 10-47 kg-m². (a) At 300 K what is the probability that the molecule is in its lowest excited vibrational state? (c) Of the molecules in the vibrational ground state what is the ratio of the number in the gronnd rotational state to the number in the first excited rotational state?arrow_forward
- Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning