Explanation Given: { 2 w + x − y = 3 w − 3 x + 2 y = − 4 3 w + x − 3 y + z = 1 w + 2 x − 4 y − z = − 2 Provided system of the equation. { 2 w + x − y = 3 w − 3 x + 2 y = − 4 3 w + x − 3 y + z = 1 w + 2 x − 4 y − z = − 2 Change into augmented matrix. [ 2 1 − 1 0 3 1 − 3 2 0 − 4 3 1 − 3 1 1 1 2 − 4 − 1 − 2 ] Now, use row operation to change bottom diagonal elements to zero and the top element to 1. Apply row operation, Interchange R 1 ↔ R 2 [ 1 − 3 2 0 − 4 2 1 − 1 0 3 3 1 − 3 1 1 1 2 − 4 − 1 − 2 ] Now, apply R 3 → R 3 − 3 R 1 , R 2 → R 2 − 2 R 1 [ 1 − 3 2 0 − 4 0 7 − 5 0 11 0 10 − 9 1 13 1 2 − 4 − 1 − 2 ] Apply R 4 → R 4 − R 1 [ 1 − 3 2 0 − 4 0 7 − 5 0 11 0 10 − 9 1 13 0 5 − 6 − 1 2 ] Apply R 3 → R 3 − 2 R 4 [ 1 − 3 2 0 − 4 0 7 − 5 0 11 0 0 3 3 9 0 5 − 6 − 1 2

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Author: Robert F. Blitzer

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Chapter 6.2, Problem 11E

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The solution to system of equation by the gaussian elimination.

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Chapter 6 Solutions

College Algebra (7th Edition)

Ch. 6.1 - A rectangular array of numbers, arranged in rows...Ch. 6.1 - Consider the matrix [ 111342211|246 ]. We can...Ch. 6.1 - Prob. 3CVC Ch. 6.1 - Using Gauss-Jordan diminution to solve the system...Ch. 6.1 - True or false: Back-substitution is required to...Ch. 6.1 - True or false: Back-substitution is required to...Ch. 6.1 - Prob. 1E Ch. 6.1 - In Exercises 18, write the augmented matrix for...Ch. 6.1 - In Exercises 1-8, write the augmented matrix for...Ch. 6.1 - In Exercises 1-8, write the augmented matrix for...

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Chapter 6 Solutions