(a) Explanation Given information: The provided model is f ( t ) = 450 t for 18 years at 7 % and tuition cost is $ 30 , 452 for one year. The provided equation is shown below: Future value = e r t 1 ∫ 0 t 1 f ( t ) e − r t d t Consider the future value from exercise 79 and 80 , Future value = e r t 1 ∫ 0 t 1 f ( t ) e − r t d t Where r is interest rate and t 1 is time period. Here the Interest rate that is, r = 7 % = 0.07 The time period that is t 1 = 18 years and model is f ( t ) = 450 t . Now substitute all the values in the future formula as: Future value = e ( 0.07 ) ⋅ 18 ∫ 0 18 450 t e − ( 0.07 ) t d t = 450 e ( 1.26 ) ∫ 0 18 t e − ( 0.07 ) t d t Now integration with respect to t and use integration by parts as: Let u = t and v = e − ( 0 (b) To determine Whether the fund is sufficient or not to cover the tuition cost after four years. If tuition cost is $ 26 , 537 for one year. If f ( t ) = 450 t for 18 years at 7 % annual interest rate by using the equation from exercise 79 and 80 .

Calculus: An Applied Approach (MindTap Course List)

10th Edition

ISBN: 9781305860919

Author: Ron Larson

Publisher: Cengage Learning

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Question

Chapter 6.1, Problem 82E

(a)

To determine

Whether the fund is sufficient or not to cover the tuition cost after four years. If tuition cost is $30,452 for one year. If f(t)=450t for 18 years at 7% annual interest rate.

(b)

To determine

Whether the fund is sufficient or not to cover the tuition cost after four years. If tuition cost is $26,537 for one year. If f(t)=450t for 18 years at 7% annual interest rate by using the equation from exercise 79 and 80.

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Chapter 6.1, Problem 81E

Chapter 6.2, Problem 1CP

Chapter 6 Solutions

Calculus: An Applied Approach (MindTap Course List)

Ch. 6.1 - Prob. 1CP Ch. 6.1 - Prob. 2CP Ch. 6.1 - Prob. 3CP Ch. 6.1 - Prob. 4CP Ch. 6.1 - Prob. 5CP Ch. 6.1 - Prob. 6CP Ch. 6.1 - Prob. 7CP Ch. 6.1 - Prob. 1SWU Ch. 6.1 - Prob. 2SWU Ch. 6.1 - Prob. 3SWU

Ch. 6.1 - Prob. 4SWU Ch. 6.1 - Prob. 5SWU Ch. 6.1 - Prob. 6SWU Ch. 6.1 - Prob. 7SWU Ch. 6.1 - Prob. 8SWU Ch. 6.1 - Prob. 9SWU Ch. 6.1 - Prob. 10SWU Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E Ch. 6.1 - Integration by Parts In Exercises 5-16, use...Ch. 6.1 - Prob. 6E Ch. 6.1 - Integration by Parts In Exercises 5-16, use...Ch. 6.1 - Prob. 8E Ch. 6.1 - Integration by Parts In Exercises 5-16, use...Ch. 6.1 - Prob. 10E Ch. 6.1 - Integration by Parts In Exercises 5-16, use...Ch. 6.1 - Prob. 12E Ch. 6.1 - Integration by Parts In Exercises 5-16, use...Ch. 6.1 - Prob. 14E Ch. 6.1 - Integration by Parts In Exercises 5-16, use...Ch. 6.1 - Prob. 16E Ch. 6.1 - Prob. 17E Ch. 6.1 - Prob. 18E Ch. 6.1 - Prob. 19E Ch. 6.1 - Prob. 20E Ch. 6.1 - Finding an Indefinite Integral In Exercises 17-38,...Ch. 6.1 - Finding an Indefinite Integral In Exercises 17-38,...Ch. 6.1 - Prob. 23E Ch. 6.1 - Prob. 24E Ch. 6.1 - Finding an Indefinite Integral In Exercises 17-38,...Ch. 6.1 - Prob. 26E Ch. 6.1 - Prob. 27E Ch. 6.1 - Prob. 28E Ch. 6.1 - Prob. 29E Ch. 6.1 - Prob. 30E Ch. 6.1 - Prob. 31E Ch. 6.1 - Prob. 32E Ch. 6.1 - Prob. 33E Ch. 6.1 - Prob. 34E Ch. 6.1 - Prob. 35E Ch. 6.1 - Prob. 36E Ch. 6.1 - Finding an Indefinite Integral In Exercises 17-38,...Ch. 6.1 - Finding an Indefinite Integral In Exercises 17-38,...Ch. 6.1 - Prob. 39E Ch. 6.1 - Prob. 40E Ch. 6.1 - Prob. 41E Ch. 6.1 - Evaluating a Definite Integral In Exercises 39-46,...Ch. 6.1 - Prob. 43E Ch. 6.1 - Prob. 44E Ch. 6.1 - Prob. 45E Ch. 6.1 - Prob. 46E Ch. 6.1 - Prob. 47E Ch. 6.1 - Prob. 48E Ch. 6.1 - Prob. 49E Ch. 6.1 - Prob. 50E Ch. 6.1 - Prob. 51E Ch. 6.1 - Prob. 52E Ch. 6.1 - Verifying Formulas In Exercises 53 and 54, use...Ch. 6.1 - Verifying Formulas In Exercises 53 and 54, use...Ch. 6.1 - Prob. 55E Ch. 6.1 - Prob. 56E Ch. 6.1 - Prob. 57E Ch. 6.1 - Prob. 58E Ch. 6.1 - Prob. 59E Ch. 6.1 - Prob. 60E Ch. 6.1 - Prob. 61E Ch. 6.1 - Prob. 62E Ch. 6.1 - Prob. 63E Ch. 6.1 - Prob. 64E Ch. 6.1 - Prob. 65E Ch. 6.1 - Revenue A company sells a seasonal product. The...Ch. 6.1 - Prob. 67E Ch. 6.1 - Prob. 68E Ch. 6.1 - Prob. 69E Ch. 6.1 - Prob. 70E Ch. 6.1 - Prob. 71E Ch. 6.1 - Prob. 72E Ch. 6.1 - Prob. 73E Ch. 6.1 - Prob. 74E Ch. 6.1 - Prob. 75E Ch. 6.1 - Prob. 76E Ch. 6.1 - Prob. 77E Ch. 6.1 - Prob. 78E Ch. 6.1 - Prob. 79E Ch. 6.1 - Future Value In Exercises 79 and 80, find the...Ch. 6.1 - Prob. 81E Ch. 6.1 - Prob. 82E Ch. 6.2 - Checkpoint 1 Use the integration table in Appendix...Ch. 6.2 - Prob. 2CP Ch. 6.2 - Prob. 3CP Ch. 6.2 - Prob. 4CP Ch. 6.2 - Checkpoint 5 Use the integration table in Appendix...Ch. 6.2 - Prob. 6CP Ch. 6.2 - Prob. 1SWU Ch. 6.2 - Prob. 2SWU Ch. 6.2 - Prob. 3SWU Ch. 6.2 - Prob. 4SWU Ch. 6.2 - Prob. 5SWU Ch. 6.2 - Prob. 6SWU Ch. 6.2 - Prob. 1E Ch. 6.2 - Prob. 2E Ch. 6.2 - Using Integration Tables In Exercises 18, use the...Ch. 6.2 - Prob. 4E Ch. 6.2 - Prob. 5E Ch. 6.2 - Prob. 6E Ch. 6.2 - Prob. 7E Ch. 6.2 - Prob. 8E Ch. 6.2 - Prob. 9E Ch. 6.2 - Prob. 10E Ch. 6.2 - Prob. 11E Ch. 6.2 - Prob. 12E Ch. 6.2 - Prob. 13E Ch. 6.2 - 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Prob. 9E Ch. 6.3 - Using the Trapezoidal Rule and Simpsons Rule In...Ch. 6.3 - Prob. 11E Ch. 6.3 - Prob. 12E Ch. 6.3 - Prob. 13E Ch. 6.3 - Prob. 14E Ch. 6.3 - Prob. 15E Ch. 6.3 - Prob. 16E Ch. 6.3 - Prob. 17E Ch. 6.3 - Prob. 18E Ch. 6.3 - Prob. 19E Ch. 6.3 - Prob. 20E Ch. 6.3 - Prob. 31E Ch. 6.3 - Prob. 32E Ch. 6.3 - Prob. 33E Ch. 6.3 - Prob. 34E Ch. 6.3 - Prob. 35E Ch. 6.3 - Prob. 36E Ch. 6.3 - Prob. 37E Ch. 6.3 - Prob. 38E Ch. 6.3 - Prob. 39E Ch. 6.3 - Error Analysis In Exercises 37-40, use the error...Ch. 6.3 - Prob. 43E Ch. 6.3 - Electricity The table shows the residential prices...Ch. 6.3 - Prob. 45E Ch. 6.3 - Prob. 46E Ch. 6.3 - Prob. 47E Ch. 6.3 - Prob. 48E Ch. 6.4 - Prob. 1CP Ch. 6.4 - Prob. 2CP Ch. 6.4 - Prob. 3CP Ch. 6.4 - Prob. 4CP Ch. 6.4 - Prob. 5CP Ch. 6.4 - Prob. 1SWU Ch. 6.4 - Prob. 2SWU Ch. 6.4 - Prob. 3SWU Ch. 6.4 - Prob. 4SWU Ch. 6.4 - Prob. 5SWU Ch. 6.4 - Prob. 6SWU Ch. 6.4 - Prob. 7SWU Ch. 6.4 - Prob. 8SWU Ch. 6.4 - Prob. 9SWU Ch. 6.4 - Prob. 10SWU Ch. 6.4 - Prob. 1E Ch. 6.4 - 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Whether the fund is sufficient or not to cover the tuition cost after four years. If tuition cost is $ 30 , 452 for one year. If f ( t ) = 450 t for 18 years at 7 % annual interest rate.

Solution Summary: The author explains how to determine whether the fund is sufficient or not to cover the tuition cost after four years.