A 1.5 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force F → = ( 1.8 t ) i ^ N (with t in seconds) is applied to the box. The acceleration of the box as a function of time t is given by a → = 0 for 0 ≤ t ≤ 2.8 s and a → = (1.2 t − 2.4) i ^ m/s 2 for t > 2.8 s. (a) What is the coefficient of static friction between the box and the surface? (b) What is the coefficient of kinetic friction between the box and the surface?
A 1.5 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force F → = ( 1.8 t ) i ^ N (with t in seconds) is applied to the box. The acceleration of the box as a function of time t is given by a → = 0 for 0 ≤ t ≤ 2.8 s and a → = (1.2 t − 2.4) i ^ m/s 2 for t > 2.8 s. (a) What is the coefficient of static friction between the box and the surface? (b) What is the coefficient of kinetic friction between the box and the surface?
A 1.5 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force
F
→
=
(
1.8
t
)
i
^
N
(with t in seconds) is applied to the box. The acceleration of the box as a function of time t is given by
a
→
= 0 for 0 ≤ t ≤ 2.8 s and
a
→
= (1.2t − 2.4)
i
^
m/s2 for t > 2.8 s. (a) What is the coefficient of static friction between the box and the surface? (b) What is the coefficient of kinetic friction between the box and the surface?
Your answer is partially correct.
A 1.3 kg box is initially at rest on a horizontal surface when at t = 0 a horizontal force = (1.8t)î N
=
(with t in seconds) is applied to the box. The acceleration of the box as a function of time t is given by a = 0
for 0 ≤ t ≤ 2.6s and a (1.38t - 2.1)î m/s² for t > 2.6 s. (a) What is the coefficient of static friction
between the box and the surface? (b) What is the coefficient of kinetic friction between the box and the
surface?
(a) Number 0.367
(b) Number
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A box rests on top of a flat bed truck. The box has a mass of m = 20 kg. The coefficient of static friction between the
box and truck is u, = 0.81 and the coefficient of kinetic friction between the box and truck is Hk = 0.62.
1) The truck accelerates from rest to v; = 16 m/s in t = 12 s (which is slow enough that the box will not slide). What is
the acceleration of the box?
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2) In the previous situation, what is the frictional force the truck exerts on the box?
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3) What is the maximum acceleration the truck can have before the box begins to slide?
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4) Now the…
A 3.00 kg box that is several hundred meters above the earth’s surface is suspended from the end of a short vertical rope of negligible mass. A time-dependent upward force is applied to the upper end of the rope and results in a tension in the rope of T(t) = (36.0 N>s)t. The box is at rest at t = 0. The only forces on the box are the tension in the rope and gravity. (a) What is the velocity of the box at (i) t = 1.00 s and (ii) t = 3.00 s? (b) What is the maximum distance that the box descends below its initial position? (c) At what value of t does the box return to its initial position?
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