Gordis Epidemiology
Gordis Epidemiology
6th Edition
ISBN: 9780323552295
Author: David D. Celentano, Moyses Szklo
Publisher: ELSEVIER
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Chapter 6, Problem 7RQ
Summary Introduction

To calculate: The probability that a person enrolled in the study will survive till the end of third year.

Introduction: Life table shows the probability of a person either diseased or health dying before their next birthday. It is also known as mortality table or actuarial table.

Expert Solution & Answer
Check Mark

Explanation of Solution

In order to find the probability that a person enrolled in the study will survive till the end of third year column 7 for all years must be found that is denoted with question mark.

(1)(2)(3)(4)(5)(6)(7)

Interval since beginning of treatment

(Months)

Alive at Beginning of intervalDied during intervalWithdrew during intervalEffective number exposed to Risk of Dying during intervalProportion who died during intervalProportion who did not die during interval
xlxdxwxl’xqxpx
1-122489627  ?
13-241255513  ?
25-3657552  ?

In order to find column 7, column 5 and column 6 for all years must be calculated.

The formula to calculate effective number of people exposed to risk of dying during interval (column5):

Effective number of people exposed to risk of dying during interval=No.ofpeoplealiveatbeginningofinterval-(12×No.ofpeoplewhowithdrewduringexperiment)l'x=lx(12×wx)

The proportion of people who died during interval is given by the below formula (column 6):

Proportion of people who died during interval=NumberofpeoplewhodiedduringtheintervalEffective number of people exposed to risk of dying during intervalqx=dxl'x

The proportion of people who did not die during interval is by the below formula (column 7):

Proportion of people who did not die during interval=1-Proportion of people who died during intervalpx=1-qx

Given:

For first year

lx=248

dx=96

wx=27

Substitute the values in the given formula for column 5:

l'x=lx(12×wx)=248(12×27)=24813.5=234.5

Substituting the values in the given formula for column 6:

qx=dxl'x=96234.5=0.409

Substituting values in the given formula for column 7:

px1=1-qx=10.409=0.591

For second year

lx=125

dx=55

wx=13

Substitute the values in the given formula for column 5:

l'x=lx(12×wx)=125(12×13)=1256.5=118.5

Substituting the values in the given formula for column 6:

qx=dxl'x=55118.5=0.464

Substituting values in the given formula for column 7:

px2=1-qx=10.464=0.536

For third year

lx=57

dx=55

wx=2

Substitute the values in the given formula for column 5:

l'x=lx(12×wx)=57(12×2)=571=56

Substituting the values in the given formula for column 6:

qx=dxl'x=5556=0.982

Substituting values in the given formula for column 7:

px3=1-qx=10.982=0.018

Add all the calculated values to the given table:

(1)(2)(3)(4)(5)(6)(7)

Interval since beginning of treatment

(Months)

Alive at Beginning of intervalDied during intervalWithdrew during intervalEffective number exposed to Risk of Dying during intervalProportion who died during intervalProportion who did not die during interval
xlxdxwxl’xqxpx
1-122489627234.50.4090.591
13-241255513118.50.4640.536
25-3657552560.9820.018

The probability that a person enrolled in the study will survive till the end of third year is:

px=px1×px2×px3=0.591×0.536×0.018=0.0057=0.006

Conclusion

The probability that a person enrolled in the study will survive till the end of third year is 0.006.

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