a. Let E = {e1,e2}, A = {a1, a2}, B = {b1},C = {c1}, RA = {(e1, a1), (e2, a2)}, RB = {(e1, b1)}, and RC = {(e1, c1)}...

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Answer 1

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Chapter 6, Problem 6PE

Explanation of Solution

a.

Let E = {e1,e2}, A = {a1, a2}, B = {b1},C = {c1}, RA = {(e1, a1), (e2, a2)}, RB = {(e1, b1)}, and RC = {(e1, c1)}...

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b.

E-R diagram:

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E-R diagram:

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Answer 2

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Chapter 6, Problem 6PE

Explanation of Solution

a.

Let E = {e1,e2}, A = {a1, a2}, B = {b1},C = {c1}, RA = {(e1, a1), (e2, a2)}, RB = {(e1, b1)}, and RC = {(e1, c1)}...

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b.

E-R diagram:

�...

Explanation of Solution

E-R diagram:

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Answer 3

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Chapter 6, Problem 6PE

Explanation of Solution

a.

Let E = {e1,e2}, A = {a1, a2}, B = {b1},C = {c1}, RA = {(e1, a1), (e2, a2)}, RB = {(e1, b1)}, and RC = {(e1, c1)}...

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b.

E-R diagram:

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Explanation of Solution

E-R diagram:

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Answer 4

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Chapter 6, Problem 6PE

Explanation of Solution

a.

Let E = {e1,e2}, A = {a1, a2}, B = {b1},C = {c1}, RA = {(e1, a1), (e2, a2)}, RB = {(e1, b1)}, and RC = {(e1, c1)}...

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b.

E-R diagram:

�...

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E-R diagram:

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Answer 5

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Answer 6

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Answer 7

Chapter 6, Problem 6PE

Explanation of Solution

a.

Let E = {e1,e2}, A = {a1, a2}, B = {b1},C = {c1}, RA = {(e1, a1), (e2, a2)}, RB = {(e1, b1)}, and RC = {(e1, c1)}...

Explanation of Solution

b.

E-R diagram:

�...

Explanation of Solution

E-R diagram:

Answer 8

Chapter 6, Problem 6PE

Explanation of Solution

a.

Let E = {e1,e2}, A = {a1, a2}, B = {b1},C = {c1}, RA = {(e1, a1), (e2, a2)}, RB = {(e1, b1)}, and RC = {(e1, c1)}...

Answer 9

Chapter 6, Problem 6PE

Explanation of Solution

a.

Let E = {e1,e2}, A = {a1, a2}, B = {b1},C = {c1}, RA = {(e1, a1), (e2, a2)}, RB = {(e1, b1)}, and RC = {(e1, c1)}...

Answer 10

Explanation of Solution

b.

E-R diagram:

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Answer 11

Explanation of Solution

b.

E-R diagram:

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Answer 12

Explanation of Solution

E-R diagram:

Answer 13

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E-R diagram:

Answer 14

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Answer 15

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Answer 16

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Answer 17

Ch. 6 - Prob. 1PE Ch. 6 - Consider a database that includes the entity sets...Ch. 6 - Design an E-R diagram for keeping track of the...Ch. 6 - Prob. 4PE Ch. 6 - Prob. 5PE Ch. 6 - Prob. 6PE Ch. 6 - Prob. 7PE Ch. 6 - Consider a relation such as sec_course, generated...Ch. 6 - Suppose the advisor relationship set were...Ch. 6 - Prob. 10PE

a. Let E = {e1,e2}, A = {a1, a2}, B = {b1},C = {c1}, RA = {(e1, a1), (e2, a2)}, RB = {(e1, b1)}, and RC = {(e1, c1)}...

Explanation of Solution

a. Let E = {e1,e2}, A = {a1, a2}, B = {b1},C = {c1}, RA = {(e1, a1), (e2, a2)}, RB = {(e1, b1)}, and RC = {(e1, c1)}...

Explanation of Solution

b. E-R diagram: �...

Explanation of Solution

E-R diagram:

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Chapter 6 Solutions

a.

Let E = {e1,e2}, A = {a1, a2}, B = {b1},C = {c1}, RA = {(e1, a1), (e2, a2)}, RB = {(e1, b1)}, and RC = {(e1, c1)}...

b.

E-R diagram:

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