Elements Of Physical Chemistry
Elements Of Physical Chemistry
7th Edition
ISBN: 9780198796701
Author: ATKINS, P. W. (peter William), De Paula, Julio
Publisher: Oxford University Press
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Chapter 6, Problem 6C.10E

(a)

Interpretation Introduction

Interpretation:

The ester concentration left after 15 seconds of reaction between ethyl acetate and sodium hydroxide with given initial concentration has to be calculated.

Concept Introduction:

Second order reaction: If here are two reactant molecules are involving in a reaction, then the order of the reaction is two. So, such a reaction is known as a second order reaction.

General representation of a second order reaction is as follows:

A+BProducts

Rate law for second order reaction is given below:

Rate=K[A][B]K=istheproportionalityconstant.

Integrated rate law for the second order reaction is given below:

[P]=[A]o[B]o(1- e([B]o-[A]o)krt)[A]o[B]oe([B]o-[A]o)krt

[A]t=concentrationofthereactantaftercertaintime't'.[A]o=initialconcentrationofthereactant.'t'=timetakenbythereactanttoattainitsfinalconcentrationfromitsinitialconcentration.

(a)

Expert Solution
Check Mark

Explanation of Solution

The ester concentration left after 15 seconds for given reaction is given as follows,

[P]=[A]o[B]o(1- e([B]o-[A]o)krt)[A]o-[B]oe([B]o-[A]o)krt[P]=(0.150×0.055)(1- e(0.055 - 0.150)0.11×15)0.150-0.055e(0.055-0.150)0.11×15=1.16×102moldm-3[CH3COOC2H5]=0.150moldm-31.16×102moldm-3=0.1384moldm-3

(b)

Interpretation Introduction

Interpretation:

The ester concentration left after 15 minutes of reaction between ethyl acetate and sodium hydroxide with given initial concentration has to be calculated.

Concept Introduction:

Second order reaction: If here are two reactant molecules are involving in a reaction, then the order of the reaction is two. So, such a reaction is known as a second order reaction.

General representation of a second order reaction is as follows:

A+BProducts

Rate law for second order reaction is given below:

Rate=K[A][B]K=istheproportionalityconstant.

Integrated rate law for the second order reaction is given below:

[P]=[A]o[B]o(1- e([B]o-[A]o)krt)[A]o[B]oe([B]o-[A]o)krt

[A]t=concentrationofthereactantaftercertaintime't'.[A]o=initialconcentrationofthereactant.'t'=timetakenbythereactanttoattainitsfinalconcentrationfromitsinitialconcentration.

(b)

Expert Solution
Check Mark

Explanation of Solution

The ester concentration left after 15 seconds for given reaction is given as follows,

[P]=[A]o[B]o(1- e([B]o-[A]o)krt)[A]o-[B]oe([B]o-[A]o)krt[P]=(0.150×0.055)(1- e(0.055 - 0.150)0.11×900)0.150-0.055e(0.055-0.150)0.11×900 here,15min=900s=5.5×102moldm-3[CH3COOC2H5]=0.150moldm-35.5×102moldm-3=0.095moldm-3

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Chapter 6 Solutions

Elements Of Physical Chemistry

Ch. 6 - Prob. 6C.4STCh. 6 - Prob. 6D.1STCh. 6 - Prob. 6D.2STCh. 6 - Prob. 6D.3STCh. 6 - Prob. 6E.1STCh. 6 - Prob. 6E.2STCh. 6 - Prob. 6F.1STCh. 6 - Prob. 6F.2STCh. 6 - Prob. 6G.1STCh. 6 - Prob. 6G.2STCh. 6 - Prob. 6G.3STCh. 6 - Prob. 6H.1STCh. 6 - Prob. 6I.1STCh. 6 - Prob. 6I.2STCh. 6 - Prob. 6A.1ECh. 6 - Prob. 6A.2ECh. 6 - Prob. 6A.3ECh. 6 - Prob. 6B.1ECh. 6 - Prob. 6B.2ECh. 6 - Prob. 6B.3ECh. 6 - Prob. 6B.4ECh. 6 - Prob. 6B.5ECh. 6 - Prob. 6C.1ECh. 6 - Prob. 6C.2ECh. 6 - Prob. 6C.3ECh. 6 - Prob. 6C.4ECh. 6 - Prob. 6C.5ECh. 6 - Prob. 6C.6ECh. 6 - Prob. 6C.7ECh. 6 - Prob. 6C.8ECh. 6 - Prob. 6C.9ECh. 6 - Prob. 6C.10ECh. 6 - Prob. 6C.11ECh. 6 - Prob. 6C.12ECh. 6 - Prob. 6D.1ECh. 6 - Prob. 6D.2ECh. 6 - Prob. 6D.3ECh. 6 - Prob. 6D.4ECh. 6 - Prob. 6D.5ECh. 6 - Prob. 6D.6ECh. 6 - Prob. 6D.7ECh. 6 - Prob. 6D.8ECh. 6 - Prob. 6D.9ECh. 6 - Prob. 6D.10ECh. 6 - Prob. 6D.11ECh. 6 - Prob. 6E.1ECh. 6 - Prob. 6E.2ECh. 6 - Prob. 6E.3ECh. 6 - Prob. 6F.1ECh. 6 - Prob. 6F.2ECh. 6 - Prob. 6F.3ECh. 6 - Prob. 6G.1ECh. 6 - Prob. 6G.2ECh. 6 - Prob. 6G.3ECh. 6 - Prob. 6G.5ECh. 6 - Prob. 6H.1ECh. 6 - Prob. 6H.2ECh. 6 - Prob. 6H.3ECh. 6 - Prob. 6H.4ECh. 6 - Prob. 6I.1ECh. 6 - Prob. 6I.2ECh. 6 - Prob. 6I.3ECh. 6 - Prob. 6.1DQCh. 6 - Prob. 6.2DQCh. 6 - Prob. 6.3DQCh. 6 - Prob. 6.4DQCh. 6 - Prob. 6.5DQCh. 6 - Prob. 6.6DQCh. 6 - Prob. 6.7DQCh. 6 - Prob. 6.8DQCh. 6 - Prob. 6.9DQCh. 6 - Prob. 6.10DQCh. 6 - Prob. 6.11DQCh. 6 - Prob. 6.12DQCh. 6 - Prob. 6.13DQCh. 6 - Prob. 6.14DQCh. 6 - Prob. 6.1PCh. 6 - Prob. 6.2PCh. 6 - Prob. 6.3PCh. 6 - Prob. 6.4PCh. 6 - Prob. 6.5PCh. 6 - Prob. 6.6PCh. 6 - Prob. 6.9PCh. 6 - Prob. 6.10PCh. 6 - Prob. 6.11PCh. 6 - Prob. 6.12PCh. 6 - Prob. 6.13PCh. 6 - Prob. 6.15PCh. 6 - Prob. 6.16PCh. 6 - Prob. 6.17PCh. 6 - Prob. 6.19PCh. 6 - Prob. 6.20PCh. 6 - Prob. 6.21PCh. 6 - Prob. 6.22PCh. 6 - Prob. 6.24PCh. 6 - Prob. 6.25PCh. 6 - Prob. 6.26PCh. 6 - Prob. 6.27PCh. 6 - Prob. 6.28PCh. 6 - Prob. 6.29PCh. 6 - Prob. 6.30P
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