(a)
Interpretation:
The
Concept Introduction:
Negative logarithm of the concentration of hydronium ion is the
(a)
Answer to Problem 6B.5E
The
Explanation of Solution
Nitric acid is a strong acid and it completely dissociates in water. This can be represented as follows;
One mole of nitric acid dissociates to give one mole of hydrogen ion and one mole of nitrate ion. Therefore,
The
Hence, the
The
Hence, the
(b)
Interpretation:
The
Concept Introduction:
Refer part (a).
(b)
Answer to Problem 6B.5E
The
Explanation of Solution
Hydrochloric acid is a strong acid and it completely dissociates in water. This can be represented as follows;
One mole of hydrochloric acid dissociates to give one mole of hydrogen ion and one mole of chloride ion. Therefore,
The
Hence, the
The
Hence, the
(c)
Interpretation:
The
Concept Introduction:
Refer part (a).
(c)
Answer to Problem 6B.5E
The
Explanation of Solution
Barium hydroxide is a strong acid and it completely dissociates in water. This can be represented as follows;
One mole of barium hydroxide dissociates to give one mole of barium ion and two moles of hydroxide ion. Therefore,
The
Hence, the
The
Hence, the
(d)
Interpretation:
The
Concept Introduction:
Refer part (a).
(d)
Answer to Problem 6B.5E
The
Explanation of Solution
Concentration of potassium hydroxide after dilution is calculated as shown below;
Therefore,
The
Hence, the
The
Hence, the
(e)
Interpretation:
The
Concept Introduction:
Refer part (a).
(e)
Answer to Problem 6B.5E
The
Explanation of Solution
Molarity of sodium hydroxide solution is calculated as shown below;
Therefore,
The
Hence, the
The
Hence, the
(f)
Interpretation:
The
Concept Introduction:
Refer part (a).
(f)
Answer to Problem 6B.5E
The
Explanation of Solution
Concentration of hydrobromic acid after dilution is calculated as shown below;
Therefore,
The
Hence, the
The
Hence, the
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Chapter 6 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM
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- 2.2 6. (i) Define pH in words. The strong acid HClaq has a pH value of 1, use the following equation for a strong acid: Haq Claq + HClaq And convert the following expression to deduce the hydrogen ion concentration: pH = -log10 [H+] (ii) Use the above expression to deduce the pH of HCl (aq) given the concentration of the acid to be 4.5 mol/dm³ pH =arrow_forwardCalculate the pH of 0.225 M RbOH(aq).arrow_forwardWhat is the pH of 0.018M C5H5N(aq)?arrow_forward
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