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Consider the footing and loads in Problem 6.7, except that the overturning moment now acts at a
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- Problem 2: The lap joint shown is fastened by 6 − 20?? diameter rivets. Assuming that ? = 200??, determine (a) the shearing stress in each rivet, (b) the bearing stress in each plate 25?? thick and 100?? wide. Assume that the axial load ? is distributed equally among the 6rivets, and the diameter of hole is 22??. See figure 102. Show complete solution.arrow_forwardGiven: Four-25-mm-diameter rivets with an axial load of T = 75 kN distributed equally as shown. The thickness of the plates is 25 mm and the width of the plate is 150 mm. find (a) the shear stress on the rivets (b) the bearing stress between a plate and a rivet; (c) the minimum average tensile stress in each plate. Show detailed solution and draw FBD.arrow_forwardProblem 2 A piece of engineering equipment is supported by the foundation shown. The diameter of the circular pin is 20 mm. 50 1250 100 SO 12 a.) Determine the value of P so as not to exceed the allowable bearing stress of 310.5 Mpa in the circular pin. b.) Determine the value of P so as not to exceed the allowable shearing stress of 138 Mpa in the circular pin.arrow_forward
- 3. A 12 inches square steel bearing plate lies between an 8 inches diameter wooden post and a concrete footing as shown in the figure. Determine the maximum value of the load P if the stress in wood is limited to 1800 psi and that in concrete to 650 psi. 8 in o Bearing Plate 12 inarrow_forwardThree loads are applied to the short rectangular post shown. The cross-sectional dimensions of the post are also shown. If F, - 104 kN, F2 - 193 kN, and F3 - 61 kN, determine the normal stress o at point H. - 50 mm 120 mm 75 mm 30 mm 150 mm 160 mm 30 mm H Cross-sectional dimensions. O 18.4 MPa O 25.3 MPa O 19.6 MPa O 15.7 MPa O O MPaarrow_forwardA 30-cm square steel bearing plate lies between a 20-cm diameter wooden post and a concrete footing as shown below. Determine the maximum value of the load P if the stress in wood is limited to 12600 kPa and that in concrete to 4550 kPa.arrow_forward
- We are interested in the forces at a footing due to dead, live, and earthquake loads. The horizontal forces are 0.7 for dead, 1.1 for live, and 4.7 for earthquake. The vertical forces are 2.3 for dead, 3.9 for live, and 3.8 for earthquake. For vertical forces, positive indicates compression and negative indicates uplift. Apply all the relevant load combinations. All forces are in kips. Determine the largest compressive vertical force in kips to two decimals.arrow_forward1. A simply supported beam 300 mm wide, 500 mm deep and spans 5.7 m supports a service super imposed dead load of 9 kN/m and service live load of 9 kN/m. Concrete strength f’c = 21 MPa and steel yield strength fy = 415 MPa. Concrete cover to bar centroid is 70 mm. Determine the depth of equivalent rectangular stress block (mm) at ultimate stage. Write your answer in 2 decimal places only. 2. A simply supported beam 300 mm wide, 500 mm deep and spans 5 m supports a service super imposed dead load of 7 kN/m and service live load of 6 kN/m. Concrete strength f’c = 21 MPa and steel yield strength fy = 415 MPa. Concrete cover to bar centroid is 70 mm. Determine the required amount of tensile reinforcement in mm^2 as per provisions of NSCP 2015. Write your final answer to the nearest whole number.arrow_forwardAn embedded beam is subjected to the loads shown. Determine the stress produced at points A, B ,C, D in the embedment section. The X axis is 72.9 mm from the top edge. Solve correctly pleasearrow_forward
- Q4: Use the rectangular loaded area to calculate the increase in vertical stresses at points (A) and (B) due to the loaded area of footing. Choose figure (1) or (2). Top view Top view it. awT CLAY 1 CLAY 1 CLAY 2 10m x 10m 150² INCOMPRESSIBLE Figure (1) B G.W.T ME CLAY 1 CLAY 1 CLAY 2 YA 10mX10m 7-15076 INCOMPRESSIBLE Figure (2)arrow_forwardIn the figure below, the wood pole is supported by cables of 0.32-in diameter. The turnbuckles in the cables are tightened until the stress in the cables reaches 60000psi. If the working compressive stress for the wood is 216psi. 59° 59° Determine the smallest permissible diameter of the pole. inches in 2 decimal placesarrow_forwardGiven: Four-25-mm-diameter rivets with an axial load of T = 75 kN distributed equally as shown. The thickness of the plates is 25 mm and width of plate is 150 mm. find (a) the shear stress on the rivets (b) the bearing stress between a plate and a rivet; (c) the minimum average tensile stress in each plate. SHOW FBD DIAGRAMarrow_forward
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