GENERAL,ORGANIC,+BIOCHEMISTRY
10th Edition
ISBN: 9781260148954
Author: Denniston
Publisher: RENT MCG
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Chapter 6, Problem 6.87QP
Interpretation Introduction
Interpretation:
The given
Concept Introduction:
Hypotonic solution is the solution which has a concentration less than that of the given solution.
Hypertonic solution is the solution which has a concentration higher than that of the given solution.
Isotonic solution is the solution which has a concentration equal to that of the given solution.
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this is an inorganic chemistry question please answer accordindly!!
its just one question with parts till (g) JUST ONE QUESTION with its parts spread out in the form of different images attached 2 IMAGES ATTACHED PLEASE SEE ALL, please answer EACH part till the end and dont just provide wordy explanations wherever asked for structures or diagrams, please DRAW DRAW them on a paper and post clearly!! answer the full question with all details EACH PART CLEARLY please thanks!!
im reposting this please solve all parts and drawit not just word explanations!!
The complex anion in Ba₂[Cr(CN)6] is a tetragonally distorted octahedral complex (Dan). Baz[Cr(CN)6] is
paramagnetic at room temperature with S = 1. Assume that the complex is a low-spin complex.
a) Identify if the [Cr(CN)6] anionic complex has 4 long and
2 short bonds (left side of figure) or if the complex has 4
short and 2 long bonds (right side of figure) with respect
to Oh symmetry. Use crystal field theory to answer this
question. Explain/rationalize your decision. Can the
provided information decide on the order of orbital
energies?
Dah
Tetragonal Distortion
ய
Dab
z-compression
z-elongation
x and y elongation
O symmetry
x and y compression
E
eg d² dx²-y²
t2g
dxy dxz dyz
Question 4 a) continued:
Provide your explanations in the space below.
b) At low temperatures Ba₂[Cr(CN)6] is ferromagnetically ordered with a phase transition to a paramagnetic
phase at Tc = 150K. Sketch the magnetic susceptibility vs. temperature in the diagram below. Indicate Tc
as well as the paramagnetic and…
Chapter 6 Solutions
GENERAL,ORGANIC,+BIOCHEMISTRY
Ch. 6.1 - Describe how you would distinguish experimentally...Ch. 6.1 - Prob. 6.2QCh. 6.1 - Explain why, over time, a bottle of soft drink...Ch. 6.1 - Prob. 6.4QCh. 6.1 - Prob. 6.5QCh. 6.1 - Prob. 6.6QCh. 6.2 - Calculate the % (m/V) of 0.0600 L of solution...Ch. 6.2 - Prob. 6.2PPCh. 6.2 - Prob. 6.3PPCh. 6.2 - Prob. 6.4PP
Ch. 6.3 - Prob. 6.5PPCh. 6.3 - Prob. 6.6PPCh. 6.3 - Prob. 6.7PPCh. 6.3 - Prob. 6.7QCh. 6.3 - Prob. 6.8QCh. 6.3 - Prob. 6.8PPCh. 6.3 - Prob. 6.9PPCh. 6.4 - Prob. 6.9QCh. 6.4 - Comparing pure water and a 0.10 m glucose...Ch. 6.4 - Prob. 6.10PPCh. 6.4 - Prob. 6.11PPCh. 6.4 - Prob. 6.12PPCh. 6.4 - Prob. 6.13PPCh. 6.4 - Prob. 6.11QCh. 6.4 - Prob. 6.12QCh. 6.5 - Prob. 6.14PPCh. 6.5 - Prob. 6.15PPCh. 6.5 - Prob. 6.16PPCh. 6.5 - Prob. 6.13QCh. 6.5 - Prob. 6.14QCh. 6 - Prob. 6.15QPCh. 6 - Prob. 6.16QPCh. 6 - Which of the following solute(s) would form an...Ch. 6 - Prob. 6.18QPCh. 6 - Prob. 6.19QPCh. 6 - Prob. 6.20QPCh. 6 - Prob. 6.21QPCh. 6 - Prob. 6.22QPCh. 6 - Prob. 6.23QPCh. 6 - Prob. 6.24QPCh. 6 - Prob. 6.25QPCh. 6 - Prob. 6.26QPCh. 6 - Prob. 6.27QPCh. 6 - Prob. 6.28QPCh. 6 - The Henry’s law constant, k, for O2 in aqueous...Ch. 6 - The Henry’s law constant, k, for N2 in aqueous...Ch. 6 - Calculate the composition of each of the following...Ch. 6 - Calculate the composition of each of the following...Ch. 6 - Calculate the composition of each of the following...Ch. 6 - Calculate the composition of each of the following...Ch. 6 - Prob. 6.35QPCh. 6 - Calculate the composition of each of the following...Ch. 6 - Prob. 6.37QPCh. 6 - Prob. 6.38QPCh. 6 - Prob. 6.39QPCh. 6 - Prob. 6.40QPCh. 6 - Prob. 6.41QPCh. 6 - Prob. 6.42QPCh. 6 - Prob. 6.43QPCh. 6 - Prob. 6.44QPCh. 6 - Which solution is more concentrated: a 0.04% (m/m)...Ch. 6 - Which solution is more concentrated: a 20 ppt...Ch. 6 - Prob. 6.47QPCh. 6 - Prob. 6.48QPCh. 6 - Prob. 6.49QPCh. 6 - Prob. 6.50QPCh. 6 - Why is it often necessary to dilute solutions in...Ch. 6 - Write the dilution expression and define each...Ch. 6 - Prob. 6.53QPCh. 6 - Prob. 6.54QPCh. 6 - Prob. 6.55QPCh. 6 - Prob. 6.56QPCh. 6 - Calculate the volume of a 0.500 M sucrose solution...Ch. 6 - Calculate the volume of a 1.00 × 10−2 M KOH...Ch. 6 - It is desired to prepare 0.500 L of a 0.100 M...Ch. 6 - A 50.0-mL sample of a 0.250 M sucrose solution was...Ch. 6 - A 50.0-mL portion of a stock solution was diluted...Ch. 6 - Prob. 6.62QPCh. 6 - Prob. 6.63QPCh. 6 - Prob. 6.64QPCh. 6 - Prob. 6.65QPCh. 6 - Prob. 6.66QPCh. 6 - Prob. 6.67QPCh. 6 - Prob. 6.68QPCh. 6 - Prob. 6.69QPCh. 6 - Prob. 6.70QPCh. 6 - Prob. 6.71QPCh. 6 - Prob. 6.72QPCh. 6 - Prob. 6.73QPCh. 6 - Prob. 6.74QPCh. 6 - Prob. 6.75QPCh. 6 - Prob. 6.76QPCh. 6 - Prob. 6.77QPCh. 6 - Prob. 6.78QPCh. 6 - Answer Questions 6.79–6.82 based on the following...Ch. 6 - Answer Questions 6.79–6.82 based on the following...Ch. 6 - Answer Questions 6.79–6.82 based on the following...Ch. 6 - Answer Questions 6.79–6.82 based on the following...Ch. 6 - Prob. 6.83QPCh. 6 - Prob. 6.84QPCh. 6 - Prob. 6.85QPCh. 6 - Prob. 6.86QPCh. 6 - Prob. 6.87QPCh. 6 - Prob. 6.88QPCh. 6 - Prob. 6.89QPCh. 6 - Prob. 6.90QPCh. 6 - Prob. 6.91QPCh. 6 - Prob. 6.92QPCh. 6 - Prob. 6.93QPCh. 6 - Prob. 6.94QPCh. 6 - Prob. 6.95QPCh. 6 - Name the two most important cations in biological...Ch. 6 - Prob. 6.97QPCh. 6 - Explain why a dialysis solution must have an...Ch. 6 - Prob. 6.99QPCh. 6 - Prob. 6.100QPCh. 6 - Prob. 6.101QPCh. 6 - Prob. 6.102QPCh. 6 - Prob. 6.103QPCh. 6 - What type of solute dissolves readily in benzene...Ch. 6 - Prob. 6.105QPCh. 6 - Prob. 6.106QPCh. 6 - Prob. 6.107QPCh. 6 - Prob. 6.108QPCh. 6 - Prob. 6.109QPCh. 6 - Prob. 6.110QPCh. 6 - Prob. 6.111QPCh. 6 - Prob. 6.112QPCh. 6 - Prob. 6.113QPCh. 6 - Prob. 6.114QPCh. 6 - Prob. 1MCPCh. 6 - Prob. 2MCPCh. 6 - Prob. 3MCPCh. 6 - Prob. 4MCPCh. 6 - Prob. 5MCPCh. 6 - Prob. 6MCPCh. 6 - Prob. 7MCPCh. 6 - Prob. 8MCPCh. 6 - Prob. 9MCPCh. 6 - Prob. 10MCP
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY