Chapter 6, Problem 6.79SP

Interpretation Introduction

Interpretation:

The number of litres of ${\text{N}}_{\text{2}}$ gas can be formed from the sodium azide reaction has to be calculated.

Concept Introduction:

Limiting reagent:

In a chemical reaction, the substance which is totally consumed at the end of the reaction is known as limiting reaction. Without the particular atom or element the reaction cannot be procced further or the product becomes limited.

Cross multiplication rule:

In science, this is rule is used to find the unknown value when the $\text{3}$ other values are given. This rule is also known as the rule of three.

$\begin{array}{l}\text{ad=bc}\text{or}\text{a=}\frac{\text{bc}}{\text{d}}\\ \text{where}\text{b,d}\text{are}\text{not}\text{zeros}\end{array}$

Number of liters of ${\text{N}}_{\text{2}}$= $\text{grams}{\text{of NaN}}_{\text{3}}\text{×}\frac{\text{1 mol of}{\text{NaN}}_{\text{3}}}{{\text{at wt of NaN}}_{\text{3}}}\text{×}\frac{\text{3}\text{mol}{\text{N}}_{\text{2}}}{\text{2}\text{mol}{\text{NaN}}_{\text{3}}}\text{×}\frac{\text{volume}}{\text{1}\text{mol}{\text{N}}_{\text{2}}}$