EBK GET READY FOR ORGANIC CHEMISTRY
2nd Edition
ISBN: 9780321830555
Author: KARTY
Publisher: VST
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 6, Problem 6.59P
Interpretation Introduction
Interpretation:
Given
Concept introduction:
The strength of an acid is its tendency to donate a proton. The strength of an acid is described by its
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
но
HO
но
он
The pK, of ascorbic acid (vitamin C) is 4.17, showing that it is slightly more acidic
than acetic acid (CH3CO0H, pKa 4.74).
(a) Show the fou
r different conjugate bases that would be formed by deprotonation
of the four different OH groups in ascorbic acid.
(b)
Compare the stabilities of these four conjugate bases, and predict which OH
group of ascorbic acid is the most acidic.
(c) Compare the most stable conjugate base of ascorbic acid with the conjugate base
of acetic acid, and suggest why these two compounds have similar acidities, even
though ascorbic acid lacks the carboxylic acid (COOH) group.
(a) Explain how NaBH, in CH;OH can reduce hemiacetal A to 1,4-butanediol (HOCH,CH,CH,CH,OH). (b) What product is
formed when A is treated with Ph;P=CHCH,CH(CH),? (c) The drug isotretinoin is formed by reaction of X and Y. What is the
structure of isotretinoin? Although isotretinoin (trade name Accutane or Roaccutane) is used for the treatment of severe acne, it
is dispensed under strict controls because it also causes birth defects.
PPha
NaOCH,CH3
HO-
isotretinoin
HO
A
Br
X
Y
(i) Draw the dissociation reaction for a carboxylic acid in water and define the Ka for this reaction. Write the equation that relates pKa to Ka.
(ii) A deprotonated carboxylic acid can be drawn in two resonance forms. Draw the two forms and explain what the term “resonance” means.
(iii) Draw an energy profile for the above dissociation reaction and describe how the profiles for a strong and a weak acid would differ.
Chapter 6 Solutions
EBK GET READY FOR ORGANIC CHEMISTRY
Ch. 6 - Prob. 6.1PCh. 6 - Prob. 6.2PCh. 6 - Prob. 6.3PCh. 6 - Prob. 6.4PCh. 6 - Prob. 6.5PCh. 6 - Prob. 6.6PCh. 6 - Prob. 6.7PCh. 6 - Prob. 6.8PCh. 6 - Prob. 6.9PCh. 6 - Prob. 6.10P
Ch. 6 - Prob. 6.11PCh. 6 - Prob. 6.12PCh. 6 - Prob. 6.13PCh. 6 - Prob. 6.14PCh. 6 - Prob. 6.15PCh. 6 - Prob. 6.16PCh. 6 - Prob. 6.17PCh. 6 - Prob. 6.18PCh. 6 - Prob. 6.19PCh. 6 - Prob. 6.20PCh. 6 - Prob. 6.21PCh. 6 - Prob. 6.22PCh. 6 - Prob. 6.23PCh. 6 - Prob. 6.24PCh. 6 - Prob. 6.25PCh. 6 - Prob. 6.26PCh. 6 - Prob. 6.27PCh. 6 - Prob. 6.28PCh. 6 - Prob. 6.29PCh. 6 - Prob. 6.30PCh. 6 - Prob. 6.31PCh. 6 - Prob. 6.32PCh. 6 - Prob. 6.33PCh. 6 - Prob. 6.34PCh. 6 - Prob. 6.35PCh. 6 - Prob. 6.36PCh. 6 - Prob. 6.37PCh. 6 - Prob. 6.38PCh. 6 - Prob. 6.39PCh. 6 - Prob. 6.40PCh. 6 - Prob. 6.41PCh. 6 - Prob. 6.42PCh. 6 - Prob. 6.43PCh. 6 - Prob. 6.44PCh. 6 - Prob. 6.45PCh. 6 - Prob. 6.46PCh. 6 - Prob. 6.47PCh. 6 - Prob. 6.48PCh. 6 - Prob. 6.49PCh. 6 - Prob. 6.50PCh. 6 - Prob. 6.51PCh. 6 - Prob. 6.52PCh. 6 - Prob. 6.53PCh. 6 - Prob. 6.54PCh. 6 - Prob. 6.55PCh. 6 - Prob. 6.56PCh. 6 - Prob. 6.57PCh. 6 - Prob. 6.58PCh. 6 - Prob. 6.59PCh. 6 - Prob. 6.60PCh. 6 - Prob. 6.61PCh. 6 - Prob. 6.62PCh. 6 - Prob. 6.63PCh. 6 - Prob. 6.64PCh. 6 - Prob. 6.65PCh. 6 - Prob. 6.66PCh. 6 - Prob. 6.67PCh. 6 - Prob. 6.68PCh. 6 - Prob. 6.69PCh. 6 - Prob. 6.70PCh. 6 - Prob. 6.71PCh. 6 - Prob. 6.72PCh. 6 - Prob. 6.73PCh. 6 - Prob. 6.74PCh. 6 - Prob. 6.75PCh. 6 - Prob. 6.76PCh. 6 - Prob. 6.77PCh. 6 - Prob. 6.78PCh. 6 - Prob. 6.79PCh. 6 - Prob. 6.80PCh. 6 - Prob. 6.81PCh. 6 - Prob. 6.82PCh. 6 - Prob. 6.83PCh. 6 - Prob. 6.84PCh. 6 - Prob. 6.85PCh. 6 - Prob. 6.86PCh. 6 - Prob. 6.87PCh. 6 - Prob. 6.88PCh. 6 - Prob. 6.1YTCh. 6 - Prob. 6.2YTCh. 6 - Prob. 6.3YTCh. 6 - Prob. 6.4YTCh. 6 - Prob. 6.5YTCh. 6 - Prob. 6.6YTCh. 6 - Prob. 6.7YTCh. 6 - Prob. 6.8YTCh. 6 - Prob. 6.9YTCh. 6 - Prob. 6.10YTCh. 6 - Prob. 6.11YTCh. 6 - Prob. 6.12YTCh. 6 - Prob. 6.13YTCh. 6 - Prob. 6.14YTCh. 6 - Prob. 6.15YTCh. 6 - Prob. 6.16YTCh. 6 - Prob. 6.17YTCh. 6 - Prob. 6.18YTCh. 6 - Prob. 6.19YTCh. 6 - Prob. 6.20YT
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Account for the fact that one carboxyl group is a considerably stronger acid than the other carboxyl group.arrow_forwardThe presence of a pi bond also makes a compound a base. With this in mind, draw the conjugate acid of ethylene, CH2=CH2.arrow_forwardDicarboxylic acids have two dissociation constants, one for the initial dissociation into a monoanion and one for the second dissociation into a dianion. For oxalic acid, HO2C—CO2H, the first ionization constant is pKal = 1.2 and the second ionization constant is pKa2 = 4.2. Why is the second carboxyl group far less acidic than the first?arrow_forward
- Predict the products of the following acid-base reactions. If the equilibrium would not result in the formation of appreciable amounts of products, you should so indicate. In each case label the stronger acid, the stronger base, the weaker acid, and the weaker base: (a) CH3CH=CH2 + NANH2 (d) CH3C=C: + CH;CH2OH → (e) CH3C=C:- + NH¾CI – | (b) CH;C=CH + NaNH2 (c) CH3CH2CH3 + NANH2 → | HASarrow_forwardWhich of the following bases is strong enough to deprotonate N,Ndimethylacetamide [CH3CON(CH3)2, pKa = 30], so that equilibrium favors the products: (a) NaNH2; (b) NaOH?arrow_forwardThe base methylamine ( CH3NH₂) has a Kb of 5.0 x 10-4. A closely related base, trimethylamine ( (CH3)3N), has a Kb of 7.4 x 10-5. a Which of the two bases is stronger? methylamine trimethylamine Correct Since methylamine has the larger K₁, methylamine is the stronger base. b Calculate the pH of a 0.38 M solution of the stronger base. pH =arrow_forward
- 2) Provide acceptable names for the following structures: | CH,—С—NН— Ph Ph — О—С- CH;arrow_forward(b) Calculate the pH of 0.0005 mol dm3 ethanoic acid when its pKa = 4.75 CH3COOH( CH3COO() + H™ Ka = pH =arrow_forwardThe following pKa values have been measured. Explain why a hydroxyl group in the para position decreases the acidity while a hydroxyl group in the meta position increases the acidity.arrow_forward
- Calculate the Ka's for the following acids: (a) Citric acid, pKa = 3.14 (b) Tartaric acid, pKa = 2.98arrow_forwardPropose you are given a mixture of naphthalene, propanoic acid, and diethyl amine. Explain, using a flow chart similar to that in #1, how you would separate these three compounds. Include all solvents and reagents, show the exact compound that is present at each juncture, and be clear about the experimental technique employed in each step.arrow_forward(a) Tsomane and Nyiko were given a task of synthesising methylenecyclohexane 2. After a brief discussion with each other, Tsomane proposed Method A to synthesise 2 from cyclohexanone 1 while Nyiko proposed Method B that started from hydroxymethylcyclohexane 3. Each student believed that their proposed method is better than the other. (Scheme below) Ph THF A Ph Ph B H₂SO4 100 °C 3 OH (iii) In analysing both these methods, are there other possible alkene products other than methylenecyclohexane 2? Use mechanistic details to support your answer.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
General Chemistry | Acids & Bases; Author: Ninja Nerd;https://www.youtube.com/watch?v=AOr_5tbgfQ0;License: Standard YouTube License, CC-BY