Chapter 6, Problem 4CA

To determine

To Fill: The blank with right inequality sign for the system of inequalities has NO solution.

Answer to Problem 4CA

  $-3y+6x<-12$

Explanation of Solution

Given information: It is given that the inequalities $y-2x\le 4$and $6x-3y\_\_-12$

Calculation:

Let’s rewrite the second inequality as $6x-3y\_\_-12$

Divide each term on both sides by -3 to get the expressions like our first one.

It gives $y-2x\_\_\_4$

Now, both have same terms. So, it needs to put opposite inequality without equal sign to make there is NO solution to the system of inequalities. So, it uses “<” Sign.

Conclusion:

Thus, $-3y+6x<-12$