Explanation Given: Diameter= 2 feet Center = 4 feet below the waterline Calculation: Consider a flat surface (a plate) is submerged vertically in a fluid of weight density δ = ρ g ( l b / f t 3 ) And the submerged portion of the plate extends from h = a to h = b on the vertical axis. Then the total force F exerted by the fluid is; F = ∫ a b δ h L ( h ) d h Where h is the depth and L ( h ) is the corresponding is the length of the horizontal approximate strip Here L ( h ) = 2 r 2 − ( r − h ) 2 . The origin is taken from the bottom of the porthole. δ = 64 l b / f t 3

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 6, Problem 29PE

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A swimming pool is 20 ft wide and 40 ft long and its bottomis an inclined plane, the shallow end having a depth of3 ft and the deep end, 9 ft. If the pool is full of water, estimatethe hydro static force on (a) the shallow end, (b) thedeep end, (c) one of the sides, and (d) the bottom of thepool.

A circular porthole that has a diameter of 1 foot. The center of the circleis 15 feet below the surface. (submerged in seawater) . Find the fluid force on the porthole, assuming that the center of the square is 15 feet below the surface.

Chapter 6 Solutions

Calculus

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The fluid force on the porthole

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Chapter 6 Solutions