Concept explainers
(a)
Interpretation : The number of moles present in 21.4 mg of nitrogen dioxide is to be calculated.
Concept Introduction :
(a)
Explanation of Solution
Given mass of nitrogen dioxide is: 21.4mg
The molar mass of nitrogen dioxide is: 46.0 g. /mol
Substitute these values in the above formula to get the number of moles.
(b)
Interpretation: The number of moles present in 1.56g of copper nitrate is to be calculated.
Concept Introduction:
(b)
Explanation of Solution
Given mass of copper nitrate = 1.56g.
Molar mass of copper nitrate = 187.56 g./mol
(c)
Interpretation: The number of moles present in 2.47 g of carbon disulfide to be calculated.
Concept Introduction:
(c)
Explanation of Solution
Given mass of carbon disulphide = 2.47g.
Molar mass of carbon disulphide = 76.1 g./mol
(d)
Interpretation: The number of moles present in 5.04g of aluminum to be calculated.
Concept Introduction:
(d)
Explanation of Solution
Given mass of copper nitrate = 5.04 g.
Molar mass of copper nitrate = 342.1 g./mol
(e)
Interpretation: The number of moles present in 1.56g of copper nitrate to be calculated.
Concept Introduction:
(e)
Explanation of Solution
Given mass of copper nitrate = 2.99g.
Molar mass of copper nitrate = 278.1 g./mol
(f)
Interpretation: The number of moles present in 62.4g of calcium carbonate to be calculated.
Concept Introduction:
(f)
Explanation of Solution
Given mass of copper nitrate = 62.4g.
Molar mass of copper nitrate = 100.0 g./mol
Chapter 6 Solutions
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