Chapter 6, Problem 1SAQ

Interpretation Introduction

To determine: $\Delta E$ for the surroundings.

Answer to Problem 1SAQ

Solution: (a) $177\text{kJ}$

Explanation of Solution

Given info:

The amount of the heat produced = 155kJ.

The amount of the work done = 22kJ.

$\Delta E=q+w$

where q is the heat produced and w is the work done.

Thus, $\Delta E=155+22=177\text{ kJ}$

Hence, $\Delta E$ for the surroundings is $177\text{kJ}$.