EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
3rd Edition
ISBN: 8220101460288
Author: Deal
Publisher: PEARSON
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Chapter 6, Problem 1IA.2Q
Summary Introduction
To determine:
The chiral center in the Fischer projection and identify it on glyceraldehyde molecules with an asterisk.
Introduction:
Fischer projection is a representation of a molecule that shows the three dimensional shape of a chiral molecule on a two-dimensional plane.
A carbon atom that is attached to four different groups is called a chiral carbon. The chiral molecule is that molecule which has a different image from its mirror image. It is non superimposable on its mirror image.
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Chapter 6 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
Ch. 6 - Prob. 6.1PPCh. 6 - Prob. 6.2PPCh. 6 - Prob. 6.3PPCh. 6 - Prob. 6.4PPCh. 6 - Prob. 6.5PPCh. 6 - Classify each of the following alcohols as a...Ch. 6 - Prob. 6.7PPCh. 6 - Prob. 6.8PPCh. 6 - Prob. 6.9PPCh. 6 - Prob. 6.10PP
Ch. 6 - Prob. 6.11PPCh. 6 - Prob. 6.12PPCh. 6 - Prob. 6.13PPCh. 6 - Prob. 6.14PPCh. 6 - Prob. 6.15PPCh. 6 - Prob. 6.16PPCh. 6 - Prob. 6.17PPCh. 6 - Prob. 6.18PPCh. 6 - Prob. 6.19PPCh. 6 - Prob. 6.20PPCh. 6 - Prob. 6.21PPCh. 6 - Prob. 6.22PPCh. 6 - When an aldehyde undergoes oxidation, the...Ch. 6 - Prob. 6.24PPCh. 6 - Prob. 6.25PPCh. 6 - Prob. 6.26PPCh. 6 - Prob. 6.27PPCh. 6 - Prob. 6.28PPCh. 6 - Prob. 6.29PPCh. 6 - Prob. 6.30PPCh. 6 - Prob. 6.31PPCh. 6 - Prob. 6.32PPCh. 6 - Prob. 6.33PPCh. 6 - Prob. 6.34PPCh. 6 - Prob. 6.35PPCh. 6 - Prob. 6.36PPCh. 6 - Prob. 6.37PPCh. 6 - Prob. 6.38PPCh. 6 - Prob. 6.39PPCh. 6 - Prob. 6.40PPCh. 6 - Prob. 6.41PPCh. 6 - Prob. 6.42PPCh. 6 - Prob. 6.43PPCh. 6 - Prob. 6.44PPCh. 6 - Prob. 6.45APCh. 6 - Prob. 6.46APCh. 6 - Prob. 6.47APCh. 6 - Prob. 6.48APCh. 6 - Prob. 6.49APCh. 6 - Prob. 6.50APCh. 6 - Prob. 6.51APCh. 6 - Prob. 6.52APCh. 6 - Prob. 6.53APCh. 6 - Classify each of the following as primary,...Ch. 6 - Prob. 6.55APCh. 6 - Prob. 6.56APCh. 6 - Prob. 6.57APCh. 6 - Prob. 6.58APCh. 6 - Prob. 6.59APCh. 6 - Prob. 6.60APCh. 6 - Prob. 6.61APCh. 6 - Prob. 6.62APCh. 6 - Prob. 6.63APCh. 6 - Prob. 6.64APCh. 6 - Prob. 6.65APCh. 6 - Prob. 6.66APCh. 6 - Prob. 6.67APCh. 6 - Prob. 6.68APCh. 6 - Prob. 6.69APCh. 6 - Draw the product of the following 1 4...Ch. 6 - Prob. 6.71APCh. 6 - Prob. 6.72APCh. 6 - Prob. 6.73APCh. 6 - Prob. 6.74APCh. 6 - Prob. 6.75APCh. 6 - Prob. 6.76APCh. 6 - Prob. 6.77CPCh. 6 - Prob. 6.78CPCh. 6 - Prob. 6.79CPCh. 6 - Prob. 6.80CPCh. 6 - How much energy is produced if a person eats 50 g...Ch. 6 - Prob. 6.82CPCh. 6 - Prob. 1IA.1QCh. 6 - Prob. 1IA.2QCh. 6 - Prob. 1IA.3QCh. 6 - Prob. 1IA.4QCh. 6 - Prob. 1IA.5QCh. 6 - Prob. 1IA.6QCh. 6 - Prob. 1IA.7QCh. 6 - Prob. 1IA.8QCh. 6 - Prob. 1IA.9QCh. 6 - Prob. 2IA.1QCh. 6 - Which oxygen n the hemiacetal product in Figure 1...Ch. 6 - Prob. 2IA.3QCh. 6 - Prob. 2IA.4QCh. 6 - Where did you place the OH for C1 (top or bottom)?Ch. 6 - Prob. 2IA.6QCh. 6 - Prob. 2IA.7QCh. 6 - Prob. 1ICCh. 6 - Prob. 2ICCh. 6 - Prob. 3ICCh. 6 - Prob. 4ICCh. 6 - Prob. 5IC
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- In the L- isomer of a Fischer projection of a monosaccharide, the -OH group furthest from the carbonyl is written O on the left of the top chiral carbon O on the right of the bottom chiral carbon O on the left of the middle chiral carbon O on the right of the top chiral carbon O on the left of the bottom chiral carbonarrow_forward4) Mono- and disaccharides contain several chiral carbon centers. As practice, label all of the chiral carbons in the following compound by placing a* next to those that are chiral. OH OH 0 HO OH OH Harrow_forwardOHC CH₂OH H OH 1. Draw the Fischer Projection of the following monosaccharide. Determine whether it has an R S configuration orarrow_forward
- Part ①Draw the correct mirror image (enantiomer) the following monosaccharide Label each as (Please Draw Both Enantiomo Dor L and the mirror) снгон C=O Ho H # OH HO- H CH2OHarrow_forwardConvert each chair conformation to an open-chain form and then to a Fischer projection. Name the monosaccharide you have drawn.arrow_forwardFor the following molecule of b-D-glucose, indicate the number of chiral centers by writing the number on the appropriate line Number of chiral carbons Circle the chiral centers in the moleculesarrow_forward
- please answer question 1 and 2arrow_forward1. Which of the following is not true to the monosaccharide below? H. ОН но- -H- но ОН ĆH2OH O It is the Fischer Projection of D-glucose. It is an aldohexose having 4 chiral centers and 24 stereoisomers. It is has a D-glucose because OH- group bonded to the highest numbered chiral C is pointing to the right. It is a polyhydroxy ketone having 8 enantiomeric pair.arrow_forwardDraw the mirror image in Fischer Projection ("flat representation").arrow_forward
- HW11 #15arrow_forward12 Which of the following statements is INCORRECT? OA chiral center is a carbon atom in a molecule with four different functional groups bonded. The simplest example of a chiral monosaccharide is glyceraldehyde (CHO-HCOH-CH,OH). () A chiral molecule is a molecule whose mirror images are superimposable. Naturally occurring monosaccharides are all the "D isomer The top (1") carbon in all carbohydrates is achiral.arrow_forwardClick the "draw structure" button to launch the drawing utility. Convert the cyclic form to an acyclic monosaccharide. CH₂OH O- H H OH HO H H OH draw structure 1b)Use a simple model to convert the following Fischer projection to a line structure showing stereochemistry Br OHC CH3 HO–|CH,CH3 H S d ww b Harrow_forward
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