(a)
Interpretation: Number of days of raw material B’s plant has is to be determined.
Concept Introduction:
The raw material which is important for the B’s plant is the steel sheets.
(b)
Interpretation: Number of days of work-in-process inventory is held between Press and Pierce and form is to be calculated.
Concept Introduction:
The work-in-progress refers to the ongoing process and waiting for completion. It is an important term used in production and
(c)
Interpretation: Number of days of work-in-process inventory is held between Pierce and form and Finish Grind is to be calculated.
Concept Introduction:
The work-in-progress refers to the ongoing process and waiting for completion. It is an important term used in production and supply chain management.
(d)
Interpretation: Number of days of work-in-process inventory is held between Finish Grind and Shipping.
Concept Introduction:
The work-in-progress refers to the ongoing process and waiting for completion. It is an important term used in production and supply chain management.
(e)
Interpretation:
Lead time of new value stream’s production.
Concept Introduction:
Lead time refers to as the latency between beginning and completion of a process.
(f)
Interpretation:
Process time of the new value stream
Concept Introduction:
Processing time is nothing but the sum of each process cycle time.
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Operations Management: Processes and Supply Chains (12th Edition) (What's New in Operations Management)
- Carol Cagle bas a repetitive manufacturing plantproducing trailer bitches in Arlington, Texas. The plant has anaverage inventory tu rnover of only 12 times per year. She hastherefore determined that she will reduce her component lotsizes. She has developed the following data for one component,the safety chain clip:Annual demand = 31,200 unitsDaily demand = 120 unitsDaily production (in 8 hours) = 960 unitsDesired lot size (I hour of production) = 120 unitsHolding cost per unit per year = $12Setup labor cost per hour = $20How many minutes of setup time should she have her plant manageraim for regarding this component?arrow_forwardBased on available information, lead time demand for PC jump drives averages 48 units (normally distributed), with a standard deviation of 5 drives. Management wants a 98% service level. Refer to the standard normal table for z-values. a) What value of Z should be applied? 2.06 b) How many drives should be carried as safety stock? your response to the nearest whole number). units (roundarrow_forwardWhat happens to availability when the MTTR (mean time between failures) decreases to zero? Is there a way to convey this circumstance correctly?arrow_forward
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