Concept explainers
A.
To determine: A model for the given compounds, the most symmetric conformation for them and if they are capable of showing optical activity.
Interpretation: A model for the given compounds is to be made, the most symmetric conformation for them is to be drawn and their ability to show optical activity is to be predicted.
Concept introduction: A chiral carbon atom is attached to four different atoms or group of atoms and shows a tetrahedral geometry. The mirror image of a chiral compound is non-super imposable. The two different forms in which a single chiral carbon can exist are referred to as enantiomers. The number of enantiomers of a molecule depends on the number of chiral centers.
B.
To determine: Each asymmetric carbon atom in part (1) marked by star and labeled as (R) or (S) and comparison of the results with predictions about the asymmetric carbons.
Interpretation: Each asymmetric carbon atom in part (1) is to be marked by star and labeled as (R) or (S) and comparison of the results with predictions about the asymmetric carbons is to be done.
Concept introduction: A chiral carbon atom is attached to four different atoms or group of atoms and shows a tetrahedral geometry. The mirror image of a chiral compound is non-super imposable. The two different forms in which a single chiral carbon can exist are referred as enantiomers. The number of enantiomers of a molecule depends on the number of chiral centers.
Want to see the full answer?
Check out a sample textbook solutionChapter 5 Solutions
Organic Chemistry (9th Edition)
- 1. Using Br2 in C2H4Br2 will result in HBr and ______. a. C2H3Cl3 b. C2H4Cl3 c. C2H2Cl3 d. none of the above 2. How many halogenation are posible in propane? a. 3 b. 8 c. 6 d. 10 3.Sulfonation of pentane will result in ________ and water. a. C5H11SO3H b. C5H12SO3H c. C5H14SO3H d. none of the above 4.Nitration of hexane will result in ________ and water. a. C6H13SO3H b. C6H15NO2 c. C6H13NO2 d. C6H14NO2 5.How many moles of O2 in heating a C12H26 (dodecane) a. 27 b. 37 c. 24 d. none of the abovearrow_forwardAn experiment (a set of experiments) that would allow you to decide whether this reaction is stereospecific. stilbene ---Br2, Acetic acid--> stilbene dibromide .arrow_forwardIn 1935, J. Bredt, a German chemist, proposed that a bicycloalkene could not have a double bond at a bridgehead carbon unless one of the rings contains at least eight carbons. This is known as Bredt’s rule. Explain why there cannot be a double bond at this position.arrow_forward
- this are enantiomer or identical plz give reason for your answer by drawing diagram step by steparrow_forwardWhich group in the following pair is assigned the higher priority in R,Snomenclature −CD3, −CH3arrow_forwardThese compounds are unreactive to NaNH2 EXCEPT a. 1-butene. b. 2-butyne. c. 2-butene. d. 1-butyne.arrow_forward
- Indicate whether each statement is true or false. (a) Butanecontains carbons that are sp2 hybridized. (b) Cyclohexaneis another name for benzene. (c) The isopropyl group containsthree sp3-hybridized carbons. (d) Olefin is anothername for alkyne.arrow_forwardExplain why the addition of HBr to alkenes A and C is regioselective, forming addition products B and D, respectively.arrow_forwardExplain why the addition of HBr to alkenes A and C is regioselective,forming addition products B and D, respectively.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning