To calculate : The model that best fits the given set of points.
The quartic model best fits the data.
Given information :
The set of points is: (−5,6)(−4,3),(0,2),(2,4) and (5,10) .
Formula used:
(n+1) Principle: For any set of n+1 points in the coordinate plane that pass the vertical line test, there is a unique polynomial of degree at most n that fits the point perfectly.
Calculation :
Here, the set of points in the data are 5 .
From the (n+1) principle, there is a unique polynomial of degree at most 4 that fits the points perfectly.
Hence, there is a quartic model that fits the data.
Let y=ax4+bx3+cx2+dx+e be the model that fits the data.
Substitute the points to get the system of equations.
Substitute (−5,6) .
y=ax4+bx3+cx2+dx+e6=a(−5)4+b(−5)3+c(−5)2+d(−5)+e6=625a−125b+25c−5d+e .............. (1)
Substitute (−4,3) .
y=ax4+bx3+cx2+dx+e3=a(−4)4+b(−4)3+c(−4)2+d(−4)+e3=256a−64b+16c−4d+e .............. (2)
Substitute (0,2) .
y=ax4+bx3+cx2+dx+e2=a(0)4+b(0)3+c(0)2+d(0)+e2=e .............. (3)
Substitute (2,4) .
y=ax4+bx3+cx2+dx+e4=a(2)4+b(2)3+c(2)2+d(2)+e4=16a+8b+4c+2d+e .............. (4)
Substitute (5,10) .
y=ax4+bx3+cx2+dx+e10=a(5)4+b(5)3+c(5)2+d(5)+e10=625a+125b+25c+5d+e .............. (5)
Write the system in the augmented matrix form:
[625−12525−516256−6416−4130000121684214625125255110]
Use calculator to solve the matrix.
From here, a=0.0047,b=−0.015,c=0.1202,d=0.7822,e=2 .
So, the model that fits the data will be:
y=0.0047x4−0.015x3+0.1202x2+0.7822x+2
Therefore, the quartic model best fits the data.
Chapter 5 Solutions
High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11
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