Electric Motor Control
10th Edition
ISBN: 9781133702818
Author: Herman
Publisher: CENGAGE L
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Chapter 57, Problem 4SQ
To determine
Explain the advantage of motor-generator type of variable speed drive over the rectifier-type DC supplies.
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Describe simply, in one(1) sentence, how we can increase the value of the armature current in a shunt dc motor in the case of an increase in load while keeping the input power supply constant?
(360 V DC serial motor has a starting current value of 60 A. Total armature resistance (Ra) value is 2 times serial field circuit total resistance (Rs) for this motor. And full load line current
value (I) is 0.1 times starting current (I). Motor is rotating with 1000 rpm value under full load conditions. Find the E (reverse EMF), armature torque (Ta), armature power (Pa)
values for this motor. If the load of this motor is changed till having a line current value as 10 A, find the new speed value of this motor as rpm (n2) and new armature torque (Ta2)
values for this situation. Be careful about your solutions to be written readable and write the answers as it was shown below inside boxes.)
EA=
Ta=
Pa=
n2 =
Ta2=
Chapter 57 Solutions
Electric Motor Control
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- The input to a 220 V dc shunt motor is 11 kW. Calculate (a) the torque developed, (b) the effi ciency, and (c) the speed at this load when the following particulars of the motor are given: no-load current = 5 A; no-load speed = 1150 rpm; armature resistance = 0.5 W; shunt-fi eld resistance = 110 W.arrow_forwardQA.2 a) b) c) d) A 480 V permanent-magnet excited DC motor has armature resistance of 1.5 . When driving a load of constant load torque at rated speed of 1200 rpm, the armature takes rated 20 A. Speed is controlled by armature voltage variation, and armature is supplied from a three-phase fully controllable bridge rectifier. Available AC voltage is three-phase 415 V, 50 Hz, interfacing transformer is not used, and armature current is continuous. The machine operates at rated speed with rated load. Determine rectifier output voltage and thyristor firing angle. Determine the rated motor torque and power. The machine operates at 25% of the rated speed with 75% of the rated load. Determine rectifier output voltage and the thyristor firing angle. A three-phase rectifier can operate with different load types at the output. One possibility is placement of a capacitor across the output. Explain when this is done and why?arrow_forwardExplain how to drive DC Motors! (there should be a description about the PWM, duty-cycle, and transistor)arrow_forward
- Electrical Engineering. Explain briefly in one sentence how do we maximize the value of the armature currentin a shunt dc motor in the event of increase load, maintaining the input power supply thesame?arrow_forwardA 5 KW, 220 V dc shunt motor has a dull load line current of 30 A. the armature circuit resistance is 0.3 ohm and the shunt field resistance is 200 ohm. The constant loss for this motor is?arrow_forwardA 36 V DC motor is listed in a catalogue as having the following specifications when operated with rated voltage: • no-load speed: 3,200 rpm, stall torque: 12 Nm. Calculate the back-emf constant, the current under stall conditions, and hence the armature resistance.arrow_forward
- 360 V DC serial motor has a starting current value of 60 A. Total armature resistance (Ra) value is 2 times serial field circuit total resistance (Rs) for this motor. And full load line currentvalue (I) is 0.1 times starting current 1.). Motor is rotating with 1000 rpm value under full load conditions. Find the EA (reverse EMF), armature torque (Ta), armature power (Pa)values for this motor. If the load of this motor is changed till having a line current value as 10 A, find the new speed value of this motor as rpm (n2) and new armature torque (Ta2)values for this situation. Be careful about your solutions to be written readable and write the answers as it was shown below inside boxes.)EA=?Ta=?Pa=?n2 =?Ta2=?arrow_forwardFor the armature controlled DC motor shown, find the transfer function. Assume the following numerical values e, = 22 V f = 5 x 10-3 oz-in/ rad/ sec -4 J = 4.27 10 oz-in.-sec² T = 10 oz-in. the stall torque rad = 480 load speed - no sec R1 e2 T ie= constant For the armature controlled DC motor shown, find the transfer function. Assume the following numerical values e122 v f = 5 x 10-3 oz-in/ rad/ sec J = 4.27 × 10 02-in.-sec 2 T = 10 oz-in. - the stall torque - no - load speed sec R1 L1 e1 constantarrow_forwardQ.b,arrow_forward
- A shunt excited DC motor with an armature lap winding is connected to a 400 V DC bus bar and has the following parameters: No. of poles Flux per pole Total number of armature conductors Back emf Armature resistance 20 mWb 522 210 V 22 Calculate the following: a) Armature current. b) Speed of the motor. c) Torque developed.arrow_forwardpower electronics and drivesarrow_forwardpower electronics and drivesarrow_forward
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