
Write a polynomial function of least degree with integral coefficients that have the given zeros.

Answer to Problem 45PPS
The equation of given zeroes −1,−1,2i is f(x)=x4+2x3+5x2+8x+4 .
Explanation of Solution
Given information:
The given zeros are −1,−1,2i .
Remember, if 2i is a zero, then −2i is also a zero according to conjugates theorem. Therefore, the factors of the polynomial functions are:
f(x)=(x−2i)(x+2i)(x+1)(x+1)
To know polynomial function, multiply first two binomials having imaginary units. Then, multiply result with the third binomial, then with the fourth.
f(x)=x2−4i2 Use difference of two squares.
f(x)=x2−4(−1) Evaluate the imaginary unit, i2=−1 .
f(x)=x2+4 Simplify.
f(x)=(x2+4)(x+1) Multiply the 3rd binomial with the result.
f(x)=x2(x)+x2(1)+4(x)+4(1) Use Foil Method
f(x)=x3+x2+4x+x Multiply.
f(x)=x(x3+x2+4x+4)+1(x3+x2+4x+4) Multiply the 4th binomial with the result.
f(x)=x4+x3+4x2+4x+x3+x2+4x+4 Use distributive property
f(x)=x4+x3+x3+4x2+x2+4x+4x+4 Rearrange terms.
f(x)=x4+2x3+5x2+8x+4 Combine like terms.
Chapter 5 Solutions
Glencoe Algebra 2 Student Edition C2014
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