Graph
Answer to Problem 32PPS
Graph of inequality
The only order pairs (2,3), (0,0) and (5,3) are in the solution set.
Explanation of Solution
Calculation: Change given inequality in slope-intercept form
Subtracting 2x on both sides
Simplify
Dividing both sides by − 3.
Simplify
The slope of the line
Plot y-intercept
Plot one more point using
Another coordinate will be
Plot points
Join the points and draw a solid line for inequality sign
Now check
We could see that only order pair s (2,3), (0,0) and (5,3) are inside shaded region.
Therefore, the order pair s (2,3), (0,0) and (5,3) are in the solution set.
Chapter 5 Solutions
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Additional Math Textbook Solutions
Basic Business Statistics, Student Value Edition
Pre-Algebra Student Edition
Elementary Statistics: Picturing the World (7th Edition)
Elementary Statistics
A First Course in Probability (10th Edition)
- 3. Write a system of linear equations in slope intercept form that has exactly one solution at the point (3, 4), such that one line has positive slope (but not 1) and the other line has negative slope (but not "1). Also write your system of equations with both equations written in standard form with out any fractions 8- 7 8 5 4 3 -2- + -8-7-6-5-4-3-2-1 1 2 3 -1 2 - ° 4 -5 - -8arrow_forward2. Write a system of linear equations in slope-intercept form has exactly one solution at the point (3, 4), such that both lines have negative slope (but neither one has slope of 1). Also write your system of equations with both equations written in standard form without any fractions. B 0 5 4 3 -2 1 -8-7-6-5-4-3-2 -1 12 3 -1 2 -3 -5 6 -7 -8arrow_forward4. Write a system of linear equations in slope-intercept form that has no solution, such that (3, 4), and (3,8) are solutions to the first equation, and (0, 4) is a solution to the second equation. Also write your system of equations with both equations written in standard form with out any fractions B 0 5 4 3 -2 + -8-7-6-5-4-3-2 -1 |- 1 2 3 -1 2 -3 4 -5 6 -7arrow_forward
- Show how you can solve the system of equations by manipulating the algebra tiles while maintaining the balances. On this side of the page, use the addition (elimination) method. Keep track of what you did at each step by writing down the corresponding equivalent equations, as well as what you did to go from one equation to the next. 1. x + 2y = 5 x-2y=1 2. 2x+y=2 x-2y= 6arrow_forwarde) x24 1) Which of these are equivalent to x³? For each expression that is equivalent to x², prove it by using the definition of exponents. For each that is not equivalent to x³, give an example using a specific value for x that shows that it represents a different number. a) (x5) d) f) 10-2 b) (x²) *|*arrow_forwardNow show how you can solve the system of equations by manipulating the algebra tiles while maintaining the balances, using the substitution method. Keep track of what you did at each step by writing down the corresponding equivalent equations, as well as what you did to go from one equation to the next. Δ 1. x + 2y = 5 x-2y=1 2. 2x + y = 2 x-2y= 6arrow_forward
- 1. Write a system of two linear equations in slope-intercept form that has exactly one solution at the point (3, 4), such that both lines have positive slope (but neither one has slope of 1) Also write your system of equations with both equations written in standard form without any fractions. 8- 7 8 5 4 3 -2- + -8-7-6-5-4-3-2-1 1 2 3 -1 2 - 4 -5 -7 -8arrow_forwardThe original idea for creating this applet comes from Steve Phelps' Graph the Line applet. Directions: 1) Examine the equation shown on the right side of the screen. 2) Reposition the 2 big points so that the line is the graph of the displayed equation. 3) Click the "Check Answer" checkbox to check. If you're correct, the app will inform you. If you're not, you'll know this as well. If you're not correct, keep trying until you position the gray line correctly. 4) After correctly graphing the line, click the "Generate New Line" button.arrow_forwardProblem 1 & 2 answers 1. One diagonal has 11 squares, then total square in total for two diagonal line is 11 + 11 - 1 = 21 . 2. Each part has 5 squares.(except middle)Multiply by 4: 5 × 4 = 20.Add the middle square: 20 + 1 = 21.arrow_forward
- 2. Now Figure out a different way you could determine how many squares there are in the figure, again without counting them all one-by-one. Briefly describe this other method:arrow_forward1. Without counting all of the squares one by one, determine how many squares there are in the figure shown. Briefly describe your method.arrow_forward54, and 68 e Problem (10 point. in standard form (a + bi): 2+i √√3-2i ksgiving Problem (2 ion to reveal Mr. Erdman's favoriarrow_forward
- Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSONContemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage LearningLinear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
- Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSONIntroduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge PressCollege Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education