Chapter 5.5, Problem 20E

To determine

To graph: The following functions on the same set of the axis, if $\text{\$}1$ is invested over a $10\text{ year}$ period, then the balance $A$ after $t\text{ years}$ is given by $A=1+0.06\left[t\right]$. The simple interest is $6\text{\%}$ and $A={\left(1+\left(\frac{0.055}{365}\right)\right)}^{\left[365t\right]}$ when compounded daily at an interest rate of $5.5\text{\%}$. And check which of the above equation grows at a greater rate.