For Exercises 108—109, use a graph to solve the equation on the given interval. Round the answer to 2 decimal places. 109. 6 cos ( x + π 6 ) = ln x on [ 0 , 2 π ] Viewing window: [ 0 , 2 π , π 2 ] by [ − 7 , 7 , 1 ]
For Exercises 108—109, use a graph to solve the equation on the given interval. Round the answer to 2 decimal places. 109. 6 cos ( x + π 6 ) = ln x on [ 0 , 2 π ] Viewing window: [ 0 , 2 π , π 2 ] by [ − 7 , 7 , 1 ]
Solution Summary: The author explains the solution of the equation 6mathrmcos(x+pi 6)= mathlnx by using the graph
Use this information to solve Exercises 133–134. A ball on a spring
is pulled 4 inches below its rest position and then released. After
t seconds, the ball's distance, d, in inches from its rest position is given by
d = -4 cos1.
133. Find all values of t for which the ball is 2 inches above its rest
position.
134. Find all values of t for which the ball is 2 inches below its rest
position.
In Exercises 128–129, an object is attached to a coiled spring. In
Exercise 128, the object is pulled down (negative direction from
the rest position) and then released. In Exercise 129, the object is
propelled downward from its rest position. Write an equation for
the distance of the object from its rest position after t seconds.
Distance from Rest
Position at t = 0
Amplitude
Period
128. 30 inches
30 inches
2 seconds
129. O inches
| inch
5 seconds
For Exercises 43–46, suppose that an object moves in simple
harmonic motion with displacement d (in centimeters) at
time t (in seconds). Determine the
a. Amplitude b. Period c. Frequency d. Phase shift
43. d = -8 cos
44. d = 5sin30Tt
45. 4 = 2an(1 -) 46. 4 = )
45. d = 2sin( t
3
46. d =
cos
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