PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
8th Edition
ISBN: 9781337904285
Author: Larson
Publisher: CENGAGE L
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Question
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Chapter 5.4, Problem 81E

(a)

To determine

The domains of the functions f and g .

(a)

Expert Solution
Check Mark

Answer to Problem 81E

The domains of the functions f and g is all the real number for h except h=0 .

Explanation of Solution

Given information:

The given functions f and g .

  f(h)=sin[(π/3)+h]sin(π/3)hg(h)=cosπ3(sinhh)sinπ3((1cosh)h)

Calculation:

  h is a denominator h=0 can’t be the domain because functions tends to infinity at h=0 .

For all other real numbers, f and g have values. The domain of f and g are all the real numbers except zero. The domain of function is all the real number for h except h=0 .

Therefore, the domains of the functions f and g is all the real number for h except h=0 .

(b)

To determine

Thevalues of the functions f and g at different value of h to complete the table.

(b)

Expert Solution
Check Mark

Answer to Problem 81E

The values of the functions f and g at different value of h shown in table.

Explanation of Solution

Given information:

The table is shown below.

    h0.010.020.050.10.20.5

      f(h)

    g(h)

Calculation:

Graphing calculator to obtain the value of function f(h) and g(h) at different point as follows.

The value of the functions f and g at different value of h .

    h0.010.020.050.10.20.5

      f(h)

    0.49570.49130.47810.45590.41040.2674
    g(h)0.49570.49130.47810.45590.41040.2674

Therefore,thevalues of the functions f and g at different value of h shown in the above table.

(c)

To determine

The graph of the functions f and g .

(c)

Expert Solution
Check Mark

Answer to Problem 81E

The graph of the functions f and g shown in the screen.

Explanation of Solution

Given information:

The given functions f and g .

  f(h)=sin[(π/3)+h]sin(π/3)hg(h)=cosπ3(sinhh)sinπ3((1cosh)h)

Calculation:

Press [WINDOW] and set the window size. Enter xmin=0,Xmax=1,Xscl=0.1,Ymin=0,Ymax=1 .

The screen look like as.

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 5.4, Problem 81E , additional homework tip  1

Press [GRAPH] .

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 5.4, Problem 81E , additional homework tip  2

Both the functions have the same value the graph coincide to each other.

Therefore, the graph of the functions f and g shown in the screen.

(d)

To determine

The conjecture about the values of the functions f and g as h0+ .

(d)

Expert Solution
Check Mark

Answer to Problem 81E

The conjecture about the values of the functions f and g as h0+ is f(h)0.5 and g(h)0.5 .

Explanation of Solution

Given information:

The given functions f and g .

  f(h)=sin[(π/3)+h]sin(π/3)hg(h)=cosπ3(sinhh)sinπ3((1cosh)h)

Calculation:

Press [TRACE] and then move the cursor to the left most point by pressing arrow keys, the graph as h0+ is as shown below.

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 5.4, Problem 81E , additional homework tip  3

From the graph and table as h0+,f(h)0.5 and g(h)0.5 .

Therefore, the conjecture about the values of the functions f and g as h0+ is f(h)0.5 and g(h)0.5 .

Chapter 5 Solutions

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)

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Prob. 68CRCh. 5 - Prob. 69CRCh. 5 - Prob. 70CRCh. 5 - Prob. 71CRCh. 5 - Prob. 72CRCh. 5 - Prob. 73CRCh. 5 - Prob. 74CRCh. 5 - Prob. 75CRCh. 5 - Prob. 76CRCh. 5 - Prob. 77CRCh. 5 - Prob. 78CRCh. 5 - Prob. 79CRCh. 5 - Prob. 80CRCh. 5 - Prob. 81CRCh. 5 - Prob. 82CRCh. 5 - Prob. 83CRCh. 5 - Prob. 84CRCh. 5 - Prob. 85CRCh. 5 - Prob. 86CRCh. 5 - Prob. 87CRCh. 5 - Prob. 88CRCh. 5 - Prob. 89CRCh. 5 - Prob. 90CRCh. 5 - Prob. 91CRCh. 5 - Prob. 92CRCh. 5 - Prob. 93CRCh. 5 - Prob. 94CRCh. 5 - Prob. 95CRCh. 5 - Prob. 96CRCh. 5 - Prob. 97CRCh. 5 - Prob. 98CRCh. 5 - Prob. 99CRCh. 5 - Prob. 100CRCh. 5 - Prob. 101CRCh. 5 - Prob. 102CRCh. 5 - Prob. 103CRCh. 5 - Prob. 104CRCh. 5 - Prob. 105CRCh. 5 - Prob. 106CRCh. 5 - Prob. 107CRCh. 5 - Prob. 108CRCh. 5 - Prob. 109CRCh. 5 - Prob. 110CRCh. 5 - Prob. 111CRCh. 5 - Prob. 112CRCh. 5 - Prob. 113CRCh. 5 - Prob. 114CRCh. 5 - Prob. 115CRCh. 5 - Prob. 116CRCh. 5 - Prob. 117CRCh. 5 - Prob. 118CRCh. 5 - Prob. 119CRCh. 5 - Prob. 120CRCh. 5 - Prob. 121CRCh. 5 - Prob. 122CRCh. 5 - Prob. 123CRCh. 5 - Prob. 124CRCh. 5 - Prob. 125CRCh. 5 - Prob. 126CRCh. 5 - Prob. 127CRCh. 5 - Prob. 128CRCh. 5 - Prob. 129CRCh. 5 - Prob. 130CRCh. 5 - Prob. 131CRCh. 5 - Prob. 132CRCh. 5 - Prob. 1CTCh. 5 - Prob. 2CTCh. 5 - Prob. 3CTCh. 5 - Prob. 4CTCh. 5 - Prob. 5CTCh. 5 - Prob. 6CTCh. 5 - Prob. 7CTCh. 5 - Prob. 8CTCh. 5 - Prob. 9CTCh. 5 - Prob. 10CTCh. 5 - Prob. 11CTCh. 5 - Prob. 12CTCh. 5 - Prob. 13CTCh. 5 - Prob. 14CTCh. 5 - Prob. 15CTCh. 5 - Prob. 16CTCh. 5 - Prob. 17CTCh. 5 - Prob. 18CTCh. 5 - Prob. 19CTCh. 5 - Prob. 20CTCh. 5 - Prob. 21CTCh. 5 - Prob. 22CTCh. 5 - Prob. 23CTCh. 5 - Prob. 24CTCh. 5 - Prob. 25CT
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