To determine The temperature change of the water. Explanation Write the expression for the change in the internal energy using the Bernoulli’s theorem. u ¯ 2 − u ¯ 1 + p 2 − p 1 ρ + g ( z 2 − z 1 ) = 0 (I) Here, the pressure at the inlet section is p 1 , the internal energy at inlet section is u ¯ 1 , the elevation at the inlet section is z 1 , the pressure at the exit section is p 2 , the internal energy at exit section is u ¯ 2 , the elevation at the exit section is z 2 and acceleration due to gravity is g . Write the expression for the temperature difference. u ¯ 2 − u ¯ 1 = 32.2 Btu / slug ⋅ °F ( T 2 − T 1 ) ( T 2 − T 1 ) = u ¯ 2 − u ¯ 1 32.2 Btu / slug ⋅ °F (II) Here, the temperature at the inlet section is T 1 and the temperature at the exit section is T 2 . Conclusion: Refer to table B.1 “Physical properties of water” to obtain the density of the water at temperature T = 40 ° F as 1.94 slug / ft 3 . Substitute 32.2 ft / s 2 for g , 1.94 slug / ft 3 for ρ , − 100 ft for ( z 2 − z 1 ) and − 12 psi for ( p 2 − p 1 ) in Equation (I). u ¯ 2 − u ¯ 1 + ( − 12 psi ) ( 1.94 slug / ft 3 ) + ( 32.2 ft / s 2 ) ( − 100 ft ) = 0 u ¯ 2 − u ¯ 1 = ( 12 psi ( 144 lb / ft 2 1 psi ) ) ( 1

Munson, Young and Okiishi's Fundamentals of Fluid Mechanics, Binder Ready Version

8th Edition

ISBN: 9781119080701

Author: Philip M. Gerhart, Andrew L. Gerhart, John I. Hochstein

Publisher: WILEY

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Chapter 5.3, Problem 95P

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The temperature change of the water.

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Chapter 5.3, Problem 94P

Chapter 5.3, Problem 96P

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Munson, Young and Okiishi's Fundamentals of Fluid Mechanics, Binder Ready Version

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