Introductory Statistics (10th Edition)
Introductory Statistics (10th Edition)
10th Edition
ISBN: 9780321989178
Author: Neil A. Weiss
Publisher: PEARSON
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Chapter 5.3, Problem 88E

The Hypergeometric Distribution. In this exercise, we discuss the hypergeometric distribution in more detail. When sampling is done without replacement from a finite population, the hypergeometric distribution is the exact probability distribution for the number of members sampled that have a specified attribute. The hypergeometric probability formula is

P ( X = x ) ( x N p ) ( n x N ( 1 p ) ) ( n N )

where X denotes the number of members sampled that have the specified attribute, N is the population size, n is the sample size, and p is the population proportion.

To illustrate, suppose that a customer purchases 4 fuses from a shipment of 250, of which 94% are not defective. Let a success correspond to a fuse that is not defective.

  1. a. Determine N, n, and p.
  2. b. Apply the hypergeometric probability formula to determine the probability distribution of the number of nondefective fuses that the customer gets.

Key Fact 5.5 shows that a hypergeometric distribution can be approximated by a binomial distribution, provided the sample size does not exceed 5% of the population size. In particular, you can use the binomial probability formula

P ( X = x ) = ( x n ) p x ( 1 p ) n x ,

with n = 4 and p = 0.94, to approximate the probability distribution of the number of nondefective fuses that the customer gets.

  1. c. Obtain the binomial distribution with parameters n = 4 and p = 0.94.
  2. d. Compare the hypergeometric distribution that you obtained in part (b) with the binomial distribution that you obtained in part (c).
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Chapter 5 Solutions

Introductory Statistics (10th Edition)

Ch. 5.1 - Space Shuttles. The National Aeronautics and Space...Ch. 5.1 - Persons per Housing Unit. From the document...Ch. 5.1 - Major Hurricanes. The Atlantic Hurricane Database...Ch. 5.1 - Childrens Gender. A certain couple is equally...Ch. 5.1 - Dice. When two balanced dice are rolled, 36...Ch. 5.1 - World Series. The World Series in baseball is won...Ch. 5.1 - Archery. An archer shoots an arrow into a square...Ch. 5.1 - Solar Eclipses. The World Almanac provides...Ch. 5.1 - Black Bear Litters. In the article Reproductive...Ch. 5.1 - All-Numeric Passwords. The technology consultancy...Ch. 5.1 - Suppose that P(Z 1.96) = 0.025. Find P(Z 1.96)....Ch. 5.1 - Suppose that T and Z are random variables. a. If...Ch. 5.1 - Prob. 23ECh. 5.2 - What concept does the mean of a discrete random...Ch. 5.2 - Comparing Investments. Suppose that the random...Ch. 5.2 - In Exercises 5.275.30, we have provided the...Ch. 5.2 - In Exercises 5.275.30, we have provided the...Ch. 5.2 - In Exercises 5.275.30, we have provided the...Ch. 5.2 - In Exercises 5.275.30, we have provided the...Ch. 5.2 - In Exercises 5.315.35, we have provided the...Ch. 5.2 - In Exercises 5.315.35, we have provided the...Ch. 5.2 - In Exercises 5.315.35, we have provided the...Ch. 5.2 - In Exercises 5.315.35, we have provided the...Ch. 5.2 - In Exercises 5.315.35, we have provided the...Ch. 5.2 - World Series. The World Series in baseball is won...Ch. 5.2 - Archery. An archer shoots an arrow into a square...Ch. 5.2 - All-Numeric Passwords. The technology consultancy...Ch. 5.2 - Expected Value. As noted in Definition 5.4 on page...Ch. 5.2 - Evaluating Investments. An investor plans to put...Ch. 5.2 - Homeowners Policy. An insurance company wants to...Ch. 5.2 - Prob. 42ECh. 5.2 - Equipment Breakdowns. 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