Explanation Given: The given expression is ( 1 2 x 2 + 1 3 x − 4 ) + ( 1 3 x 2 + 1 6 x − 5 ) . Calculation: To find the value, remove the parenthesis and combine the like terms, ( 1 2 x 2 + 1 3 x − 4 ) + ( 1 3 x 2 + 1 6 x − 5 ) = 1 2 x 2 + 1 3 x − 4 + 1 3 x 2 + 1 6 x − 5 = ( 1 2 x 2 + 1 3 x 2 ) + ( 1 3 x + 1 6 x ) + ( − 4 − 5 ) = ( 1 2 + 1 3 )

Beginning Algebra: Early Graphing (4th Edition)

4th Edition

ISBN: 9780134178974

Author: John Tobey Jr., Jeffrey Slater, Jamie Blair, Jenny Crawford

Publisher: PEARSON

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Chapter 5.3, Problem 15E

To determine

The addition of the expression.

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Chapter 5.3, Problem 14E

Chapter 5.3, Problem 16E

Chapter 5 Solutions

Beginning Algebra: Early Graphing (4th Edition)

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