Bundle: College Physics: Reasoning And Relationships, 2nd + Webassign Printed Access Card For Giordano's College Physics, Volume 1, 2nd Edition, Multi-term
2nd Edition
ISBN: 9781133904168
Author: Nicholas Giordano
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 5, Problem 9Q
To determine
Obtain a relationship between the orbital period and orbital radius, and compare the result with the Kepler’s third law.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
You are a scientist exploring a mysterious planet. You have performed measurements and know the following things:
The planet has radius d. It is orbiting his star in a circular orbit of radius b. it takes time T to complete one orbit around the star. the free-fall acceleration on the surface of the planet is a.
Derive an expression for the mass and of the star in terms of b,T, and G the universal gravitational constant.
You are working at a summer internship for
NASA, working to study exoplanets (planets we
have detected around other stars). Calculate the
orbital radius (distance of the planet to the star)
of the newly detected planet Beta Sirius, if its'
orbital period around its star is 5.51 x 107 s.
You know from the data that the star has a
mass of 2.21 x 1029 kg, and a radius of 2.70 x
106 and the planet has a mass of 3.00 x 1022
kg.
Your Answer:
Answer
Two lead spheres are separated by 0.207 m, centre-to-centre. One sphere has a mass of 5.53 kg. The gravitational attraction between the spheres is 6.06x108N. What is the mass of the other sphere? Express your result in SI units but don't include the units in your answer.
Chapter 5 Solutions
Bundle: College Physics: Reasoning And Relationships, 2nd + Webassign Printed Access Card For Giordano's College Physics, Volume 1, 2nd Edition, Multi-term
Ch. 5.1 - Velocity and Acceleration in Circular Motion...Ch. 5.1 - Prob. 5.2CCCh. 5.2 - Prob. 5.3CCCh. 5.3 - Prob. 5.5CCCh. 5.4 - Prob. 5.6CCCh. 5.4 - Prob. 5.7CCCh. 5 - Prob. 1QCh. 5 - Prob. 2QCh. 5 - Prob. 3QCh. 5 - Consider the Cavendish experiment in Figure 5.22....
Ch. 5 - Prob. 5QCh. 5 - Prob. 6QCh. 5 - Prob. 7QCh. 5 - What force makes it possible for a car to move...Ch. 5 - Prob. 9QCh. 5 - Prob. 10QCh. 5 - Prob. 11QCh. 5 - Prob. 12QCh. 5 - Prob. 13QCh. 5 - Prob. 14QCh. 5 - Prob. 15QCh. 5 - Prob. 16QCh. 5 - Prob. 17QCh. 5 - Prob. 18QCh. 5 - Plutos mass. In 1978, it was discovered that Pluto...Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10PCh. 5 - A compact disc spins at 2.5 revolutions per...Ch. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Consider the motion of a rock tied to a string of...Ch. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 29PCh. 5 - Consider a Ferris wheel in which the chairs hang...Ch. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 64PCh. 5 - Prob. 65PCh. 5 - Prob. 66PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - A rock of mass m is tied to a string of length L...Ch. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- What is the orbital radius of an Earth satellite having a period of 1.00 h? (b) What is unreasonable about this result?arrow_forwardModel the Moons orbit around the Earth as an ellipse with the Earth at one focus. The Moons farthest distance (apogee) from the center of the Earth is rA = 4.05 108 m, and its closest distance (perigee) is rP = 3.63 108 m. a. Calculate the semimajor axis of the Moons orbit. b. How far is the Earth from the center of the Moons elliptical orbit? c. Use a scale such as 1 cm 108 m to sketch the EarthMoon system at apogee and at perigee and the Moons orbit. (The semiminor axis of the Moons orbit is roughly b = 3.84 108 m.)arrow_forwardLet gM represent the difference in the gravitational fields produced by the Moon at the points on the Earths surface nearest to and farthest from the Moon. Find the fraction gM/g, where g is the Earths gravitational field. (This difference is responsible for the occurrence of the lunar tides on the Earth.)arrow_forward
- To find some of the parameters characterizing an object moving in a circular orbit.The motivation for Isaac Newton to discover his laws of motion was to explain the properties of planetary orbits that were observed by Tycho Brahe and analyzed by Johannes Kepler. A good starting point for understanding this (as well as the speed of the space shuttle and the height of geostationary satellites) is the simplest orbit: a circular one. This problem concerns the properties of circular orbits for a satellite orbiting a planet of mass M. For all parts of this problem, where appropriate, use G for the universal gravitational constant. Find the orbital speed v of a satellite in a circular orbit of radius R around a planet of mass M . Express the orbital speed in terms of G , M , and R . Find the kinetic energy K of a satellite with mass m in a circular orbit of radius R around a planet of mass M . Express your answer in terms of m , M , G , and R . Find the satellite's orbital…arrow_forwardIn recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets are in orbits that are similar to that of earth, which orbits the sun (MsunMsun = 1.99× 10^30kg) at a distance of 1.50 × 10^11 m, called 1 astronomical unit (1 auau). Others have extreme orbits that are much different from anything in our solar system. The following problem relates to one of these planets that follows circular orbit around its star. WASP-32b orbits with a period of only 2.7 days a star with a mass that is 1.1 times that of the sun. How many au from the star is this planet? Assume the orbital period of earth is 365 days.arrow_forwardA satellite has an orbital radius of 100km above the earth's surface. Earths mass= 5.97x10^24kg. Earths radius=6.38x10^6. What is the speed of the satellite? How many minutes does it take the satellite to complete one orbit?arrow_forward
- Scientists determine the masses of planets by observing the effect of the gravitational field of those planets on nearby objects - mainly upon their moons. By measuring the orbital period and orbital radius of a moon about a planet, Newton's laws of motion can be used to determine the mass of the planet. Phobos, a moon of the planet Mars, was discovered in 1877. It's orbital radius is 9380 km and its orbital period is 0.319 days (2.77 x 104 seconds). Determine the mass of Mars based on this data.arrow_forwardWhich of the following statements cannot be supported by Kepler's laws of planetary motion? a The distance of a planet around the sun changes throughout its orbit. b The speed a planet is moving around the sun changes throughout the year. c The orbital period of Mercury can be calculated using the orbital period of Jupiter and the average distances of both planets. d The age of the four largest planets can be determined using the age of the four smallest planets and the average distances of each planet.arrow_forwardA 200 kg satellite is orbiting around the Earth at an altitude of 35768 km above Earth's equator. Since the Earth's radius is 6378 km, the satellite is (35768 km + 6378 km) = 42146 km from the center of the Earth. (The mass of the Earth is 5,972 x 1024 kg.) a) What is the gravitational force between the Earth and the satellite? b) What is the acceleration of the satellite due to this gravitational force? c) Assuming the satellite is orbiting the Earth in a circular orbit, what is the speed of the satellite? d) How long does it take the satellite to complete one orbit around the Earth? Show your answer in unit of day.,arrow_forward
- On October 15, 2001, a planet was discovered orbiting around the star HD68988. Its orbital distance was measured to be Part A 10.5 million kilometers from the center of the star, and its orbital period was estimated at 6.3 days. What is the mass of HD68988? For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Kepler's third law. Express your answer in kilograms. ΑΣφ ? M = kg Submit Request Answer Part B What is the mass of HD68988? Express your answer in terms of our sun's mass. M = Msun Submit Request Answerarrow_forwardIn recent years, scientists have discovered hundreds of planets orbiting other stars. Some of these planets are in orbits that are similar to that of earth, which orbits the sun (MsunMsun = 1.99 ×× 103030 kgkg) at a distance of 1.50 ×× 101111 mm, called 1 astronomical unit (1 auau). Others have extreme orbits that are much different from anything in our solar system. The following problem relates to one of these planets that follows circular orbit around its star. WASP-32b orbits with a period of only 2.7 days a star with a mass that is 1.1 times that of the sun. How many au from the star is this planet? Assume the orbital period of earth is 365 days. Express your answer in astronomical units.arrow_forwardUsing canonical units, What is the circular velocity of a satellite orbiting the earth at a radius of 1.50? (Answer: 0.816). What is the radius and altitude of a satellite orbiting the earth with a period of 10.0? (Answer: radius = 1.363, altitude = 0.363)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Classical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Classical Dynamics of Particles and Systems
Physics
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Kepler's Three Laws Explained; Author: PhysicsHigh;https://www.youtube.com/watch?v=kyR6EO_RMKE;License: Standard YouTube License, CC-BY