EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
7th Edition
ISBN: 9780100257047
Author: Chang
Publisher: YUZU
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Chapter 5, Problem 5.57QP
Interpretation Introduction

Interpretation:

The partial pressures of the given gases have to be calculated.

Concept Introduction:

A mole fraction is the unit less proportion of the number of moles of a mixture constituent and the total number of moles in the mixture.

χi=PiPtotal

The number of molecules of gases is known. Since the mole fraction is:

nintotal=moleculesofi6.022×1023molecules/molmoleculestotal6.022×1023molecules/mol=moleculesofimoleculestotal

  • In a mixture of gases, every gas has an incomplete pressure which is the theoretical stress of that gas if it alone engaged the entire volume of the original combination at the same temperature.
  • The sum pressure of an ideal gas mixture is the amount of the partial pressures of the gases in the mixture.

Expert Solution & Answer
Check Mark

Answer to Problem 5.57QP

The partial pressure of CH4 gas was found to be 0.54atm

The partial pressure of C2H6 gas was found to be 0.44atm

The partial pressure of C3H8 gas was found to be 0.51atm

Explanation of Solution

First, we calculate the mole fraction Methane from the mixture.  Then, we can calculate the partial pressure of each component.

The number of moles of the combined gases is:

n=nCH4+nC2H6+nC3H8=0.31mol+0.25mol+0.29mol=0.85mol

χCH4=0.31mol0.85mol=0.36The partial pressure of MethanePCH4=χCH4×Ptotal=0.36×1.50atm=0.54atm

The partial pressure of CH4 gas is calculated by plugging in the values of the given pressure of gas and number of moles of the combined gas.  The partial pressure of CH4 gas was found to be 0.54atm

Second, we calculate the mole fraction Ethane from the mixture.  Then, we can calculate the partial pressure of each component.

The number of moles of the combined gases is:

n=nCH4+nC2H6+nC3H8=0.31mol+0.25mol+0.29mol=0.85mol

χC2H6=0.25mol0.85mol=0.29The partial pressure of EthanePC2H6=χC2H6×Ptotal=0.29×1.50atm=0.44atm

The partial pressure of C2H6 gas is calculated by plugging in the values of the given pressure of gas and number of moles of the combined gas.  The partial pressure of C2H6 gas was found to be 0.44atm

Third, we calculate the mole fraction Propane from the mixture.  Then, we can calculate the partial pressure of each component.

The number of moles of the combined gases is:

n=nCH4+nC2H6+nC3H8=0.31mol+0.25mol+0.29mol=0.85mol

χC3H8=0.29mol0.85mol=0.34The partial pressure of PropanePC3H8=χC3H8×Ptotal=0.34×1.50atm=0.51atm

The partial pressure of C3H8 gas is calculated by plugging in the values of the given pressure of gas and number of moles of the combined gas.  The partial pressure of C3H8 gas was found to be 0.51atm

Conclusion

The partial pressures of the given gases were calculated.

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Chapter 5 Solutions

EBK GENERAL CHEMISTRY: THE ESSENTIAL CO

Ch. 5.5 - Prob. 1PECh. 5.5 - Prob. 2PECh. 5.5 - Prob. 1RCCh. 5.6 - Prob. 1PECh. 5.6 - Prob. 2PECh. 5.6 - Prob. 1RCCh. 5.7 - Prob. 1PECh. 5.7 - Prob. 1RCCh. 5 - Prob. 5.1QPCh. 5 - Prob. 5.2QPCh. 5 - Prob. 5.3QPCh. 5 - Prob. 5.4QPCh. 5 - Prob. 5.5QPCh. 5 - 5.6 Describe what would happen to the column of...Ch. 5 - Prob. 5.7QPCh. 5 - 5.8 Is the atmospheric pressure in a mine that is...Ch. 5 - 5.9 What is the difference between a gas and a...Ch. 5 - Prob. 5.10QPCh. 5 - Prob. 5.11QPCh. 5 - Prob. 5.12QPCh. 5 - Prob. 5.13QPCh. 5 - 5.14 The atmospheric pressure at the summit of Mt....Ch. 5 - 5.15 State the following gas laws in words and...Ch. 5 - Prob. 5.17QPCh. 5 - Prob. 5.18QPCh. 5 - 5.19 A gas occupying a volume of 725 mL at a...Ch. 5 - 5.20 At 46°C a sample of ammonia gas exerts a...Ch. 5 - Prob. 5.21QPCh. 5 - Prob. 5.22QPCh. 5 - Prob. 5.23QPCh. 5 - Prob. 5.24QPCh. 5 - Prob. 5.25QPCh. 5 - Prob. 5.26QPCh. 5 - Prob. 5.27QPCh. 5 - Prob. 5.28QPCh. 5 - Prob. 5.29QPCh. 5 - Prob. 5.30QPCh. 5 - Prob. 5.31QPCh. 5 - Prob. 5.32QPCh. 5 - Prob. 5.33QPCh. 5 - Prob. 5.34QPCh. 5 - Prob. 5.35QPCh. 5 - 5.36 The temperature of 2.5 L of a gas initially...Ch. 5 - Prob. 5.37QPCh. 5 - Prob. 5.38QPCh. 5 - Prob. 5.39QPCh. 5 - Prob. 5.40QPCh. 5 - Prob. 5.41QPCh. 5 - Prob. 5.42QPCh. 5 - Prob. 5.43QPCh. 5 - Prob. 5.44QPCh. 5 - Prob. 5.45QPCh. 5 - Prob. 5.46QPCh. 5 - Prob. 5.47QPCh. 5 - Prob. 5.48QPCh. 5 - Prob. 5.49QPCh. 5 - Prob. 5.50QPCh. 5 - Prob. 5.51QPCh. 5 - Prob. 5.52QPCh. 5 - Prob. 5.53QPCh. 5 - Prob. 5.54QPCh. 5 - Prob. 5.55QPCh. 5 - Prob. 5.56QPCh. 5 - Prob. 5.57QPCh. 5 - Prob. 5.58QPCh. 5 - Prob. 5.59QPCh. 5 - Prob. 5.60QPCh. 5 - Prob. 5.61QPCh. 5 - Prob. 5.62QPCh. 5 - Prob. 5.63QPCh. 5 - Prob. 5.64QPCh. 5 - Prob. 5.65QPCh. 5 - Prob. 5.66QPCh. 5 - Prob. 5.67QPCh. 5 - Prob. 5.68QPCh. 5 - 5.69 What does the Maxwell speed distribution...Ch. 5 - Prob. 5.70QPCh. 5 - Prob. 5.71QPCh. 5 - Prob. 5.72QPCh. 5 - Prob. 5.73QPCh. 5 - Prob. 5.74QPCh. 5 - Prob. 5.75QPCh. 5 - Prob. 5.76QPCh. 5 - Prob. 5.78QPCh. 5 - 5.79 Write the van der Waals equation for a real...Ch. 5 - Prob. 5.80QPCh. 5 - Prob. 5.81QPCh. 5 - Prob. 5.82QPCh. 5 - 5.83 Discuss the following phenomena in terms of...Ch. 5 - Prob. 5.84QPCh. 5 - Prob. 5.85QPCh. 5 - Prob. 5.86QPCh. 5 - Prob. 5.87QPCh. 5 - 5.88 Identify the Maxwell speed distribution...Ch. 5 - Prob. 5.89QPCh. 5 - Prob. 5.90QPCh. 5 - Prob. 5.91QPCh. 5 - Prob. 5.92QPCh. 5 - Prob. 5.93QPCh. 5 - Prob. 5.94QPCh. 5 - Prob. 5.95QPCh. 5 - Prob. 5.96QPCh. 5 - Prob. 5.97QPCh. 5 - Prob. 5.98QPCh. 5 - Prob. 5.99QPCh. 5 - Prob. 5.100QPCh. 5 - Prob. 5.101QPCh. 5 - Prob. 5.102QPCh. 5 - Prob. 5.104QPCh. 5 - Prob. 5.105QPCh. 5 - Prob. 5.106QPCh. 5 - Prob. 5.107QPCh. 5 - Prob. 5.108QPCh. 5 - Prob. 5.109QPCh. 5 - Prob. 5.110QPCh. 5 - Prob. 5.111QPCh. 5 - Prob. 5.112QPCh. 5 - Prob. 5.113QPCh. 5 - Prob. 5.114QPCh. 5 - Prob. 5.115QPCh. 5 - Prob. 5.116QPCh. 5 - Prob. 5.117QPCh. 5 - 5.118 Apply your knowledge of the kinetic theory...Ch. 5 - Prob. 5.119SPCh. 5 - Prob. 5.120SPCh. 5 - Prob. 5.121SPCh. 5 - Prob. 5.122SPCh. 5 - Prob. 5.123SPCh. 5 - Prob. 5.124SPCh. 5 - Prob. 5.125SPCh. 5 - Prob. 5.126SPCh. 5 - Prob. 5.127SPCh. 5 - Prob. 5.128SP
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