Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN: 9781305632134
Author: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher: Cengage Learning
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Chapter 5, Problem 5.55P
To determine
The percent voltage regulation for the given condition and then the impedance of the each shunt reactor.
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400Ω
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Three 15MVA, 30kV synchronous generators A, B, and C are connected via three
reactors to a common bus bar, as shown in Figure below. The neutrals of generators A
and B are solidly grounded, and the neutral of generator C is grounded through a
reactor of 2. Q. The generator data and the reactance of the reactors are tabulated
below. A line-to-ground fault occurs on phase a of the common bus bar. Neglect
prefault currents and assume generators are operating at their rated voltage. Determine
the fault current in phase a.
GB
Gc
Item
GA
GB
Gc
0.25 pu 0.155 pu 0.056 pu
0.20 pu 0.155 pu 0.056 pu
0.20 pu 0.155 pu 0.060 pu
6.0 ?
REACTOR
Reactor
6.0
6.0
Determine the flow of active and reactive powers at the ends of the line: (Figure below)
Chapter 5 Solutions
Power System Analysis and Design (MindTap Course List)
Ch. 5 - Representing a transmission line by the two-port...Ch. 5 - The maximum power flow for a lossy line is...Ch. 5 - Prob. 5.21MCQCh. 5 - A 30-km, 34.5-kV, 60-Hz, three-phase line has a...Ch. 5 - A 200-km, 230-kV, 60-Hz, three-phase line has a...Ch. 5 - The 100-km, 230-kV, 60-Hz, three-phase line in...Ch. 5 - The 500-kV, 60-Hz, three-phase line in Problems...Ch. 5 - A 40-km, 220-kV, 60-Hz, three-phase overhead...Ch. 5 - A 500-km, 500-kV, 60-Hz, uncompensated three-phase...Ch. 5 - The 500-kV, 60-Hz, three-phase line in Problems...
Ch. 5 - A 350-km, 500-kV, 60-Hz, three-phase uncompensated...Ch. 5 - Rated line voltage is applied to the sending end...Ch. 5 - A 500-kV, 300-km, 6()-Hz, three-phase overhead...Ch. 5 - The following parameters are based on a...Ch. 5 - Consider a long radial line terminated in its...Ch. 5 - For a lossless open-circuited line, express the...Ch. 5 - A three-phase power of 460 MW is transmitted to a...Ch. 5 - Prob. 5.55PCh. 5 - Consider the transmission line of Problem 5.18....Ch. 5 - Given the uncompensated line of Problem 5.18, let...
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- Q2. Figure Q2 shows the single-line diagram. The scheduled loads at buses 2 and 3 are as marked on the diagram. Line impedances are marked in per unit on 100 MVA base and the line charging susceptances are neglected. a) Using Gauss-Seidel Method, determine the phasor values of the voltage at load bus 2 and 3 according to second iteration results. b) Find slack bus real and reactive power according to second iteration results. c) Determine line flows and line losses according to second iteration results. d) Construct a power flow according to second iteration results. Slack Bus = 1.04.20° 0.025+j0.045 0.015+j0.035 0.012+j0,03 3 |2 134.8 MW 251.9 MW 42.5 MVAR 108.6 MVARarrow_forwardDiscuss the role of FACTS (Flexible Alternating Current Transmission Systems) devices in power system control and optimization.arrow_forward5.26 An unloaded generator with a pre-fault voltage ct 1 pu has the following sequence impedance: Z, = j0. 15 pu, Z, = Z, = j0.25 pu The neutral is grounded with a reactance of 0.05 pu. The fault current in pu for a single-line to ground fault is (a) 3.75 pu (c) 6 pu (b) 4.28 pu (d) 7.25 puarrow_forward
- 5.10 The zero sequence current of a generator for line to ground fault is j2.4 p.u. Then the current through the neutral during the fault is (a) j2.4 p.u. (b) j0.8 p.u. (c) j7.2 p.u. (d) j0.24 p.u.arrow_forwardThe one-line diagram of a simple power system is shown in Figure below. The neutral of each generator is grounded through a current-limiting reactor of 0.25/3 per unit on a 100-MVA base. The system data expressed in per unit on a common 100-MVA base is tabulated below. The generators are running on no-load at their rated voltage and rated frequency with their emfs in phase. G Stark Item Base MVA Voltage Rating X' x² 20 kV 20 kV 20/220 kV 20/220 kV 100 0.05 0.15 0.15 0.10 0.10 220 kV 0.125 0.125 0.30 0.15 0.25 025 0.7125 0.15 100 100 0.15 0.05 0.10 0.10 0.10 100 0.10 100 100 Lu La 220 kV 0.15 220 kV 0.35 100 A balanced three-phase fault at bus 3 through a fault impedance Zf= jo.I per unit. The magnitude of the fault current in amperes in phase b for this fault is: Select one: A. 345.3 B. 820.1 C. 312500 3888888 产产arrow_forward5.10 The zero sequence current of a generator for line to ground fault is /2.4 p.u. Then the current through the neutral during the fault is (a) j2.4 p.u. (c) j7.2 p.u. (b) j0.8 p.u. (d) j0.24 p.u.arrow_forward
- Discuss the phase shift method of generating SSB through this block diagram.arrow_forwardQ5: A generator is connected through a transformer to a synchronous motor. Reduced to the same base, the per unit subtransient reactances of the generator and motor are 0.15 and 0.35, respectively, and the leakage reactance of the transformer is 0.1 per uint. A three-phase fault occurs at the terminals of the motor when the terminal voltage of the generator is 0.9 per uint and the output current of the generator is 1 per unit at 0.8 power factor leading. Find the subtransient current in per unit in the fault, in the generator, and in the motor. Use the terminal voltage of the generator as the reference phasor and obtain the solution (a) by using the internal voltages of the machines and (b) by using Thevenin's theorem.arrow_forwardThe sample large power system network data's are given below, The total number of buses is 5 Three-phase short circuit fault subjected at the bus 5 The initial voltage of the faulted bus is 1.0 p.u The Zbus matrix element Z55 is 0.704 p.u Fault impedance Zf= 0.33 p.u Fault current (If )in p.u ..........arrow_forward
- Q5 The single-line diagram of a three-phase power system is shown in Figure Q5a, with equipment ratings given in Table Q5a. (a) (b) G₁ G₂ G3 G4 T₁ T₂ T3 TA Draw the zero, positive and negative-sequence reactance diagrams using 1000 MVA, 765 kV base in the zone of Line 1-2, neglect the (A-Y) transformer phase shifts. Calculate the short circuit current as a result of three-phase bolted fault occurred at bus 1. Line 1-2 Line 1-3 Line 2-3 bus 1 0 Υ ΔΥ Line 1-3 Line 1-2 G₂ Line 2-3 bus 2 Da Figure 05a bus 3 Table Q5a T₂ KEY YE my 1000 MVA, 15 kV, X₁-X₂-0.18 p.u., Xo = 0.07, p.u. 1000 MVA, 15 kV, X₁-X₂-0.20 p.u., Xo = 0.10, p.u. 500 MVA, 13.8 kV, X₁-X₂-0.15 p.u., Xo = 0.05, p.u. X₂ = 0.05 p.u. 750 MVA, 13.8 kV, X₁-0.3 p.u., X₂-0.4 p.u., Xo = 0.1, p.u. 1000 MVA, 15 kV (A) / 765 kV (Y), XTI = 0.10 p.u. 1000 MVA, 15 kV (A)/ 765 kV (Y), XT2 = 0.10 p.u. 500MVA, 15 kV (Y) / 765 kV (Y), XT3 = 0.12 p.u. 750 MVA, 15 kV (Y)/765 kV (Y), XT4 = 0.11 p.u. Χ = 50 Ω, X = 150 Ω. Χ = 40 Ω, Χρ = 100 Ω. Χρ= 40…arrow_forward1. FIGURE 52 shows the one-line diagram of a simple three-bus power system with generation at bus I. The voltage at bus l is V1 = 1.0L0° per unit. The scheduled loads on buses 2 and 3 are marked on the diagram. Line impedances are marked in per unit on a 100 MVA base. For the purpose of hand calculations, line resistances and line charging susceptances are neglected a) Using Gauss-Seidel method and initial estimates of Va 0)-1.0+)0 and V o)- ( 1.0 +j0, determine V2 and V3. Perform two iterations (b) If after several iterations the bus voltages converge to V20.90-j0.10 pu 0.95-70.05 pu determine the line flows and line losses and the slack bus real and reactive power. 2 400 MW 320 Mvar Slack 0.0125 0.05 300 MW 270 Mvar FIGURE 52arrow_forward2. Contribution of load flow studies to erect new power station?arrow_forward
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