Solution Manual for Quantitative Chemical Analysis
Solution Manual for Quantitative Chemical Analysis
9th Edition
ISBN: 9781464175633
Author: Daniel Harris
Publisher: Palgrave Macmillan Higher Ed
Question
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Chapter 5, Problem 5.23P

(a)

Interpretation Introduction

Interpretation:

An expression for the final concentration [Cu2+]f after dilution has to be expressed.

Concept Introduction:

Standard addition,

Standard addition are the addition of known quantities of analyte to unknown solution, with the increase in linearity we can deduce that how much analyte present in the original unknown solution.

Standardadditionequation=[X]i[S]f+[X]f=IXIS+X...(1)

Where,

[X]i = The concentration of analyte in initial solution.

[S]f+[X]f = The concentration of analyte plus standard in final solution.

IX = Signal from the initial solution

IS+X =signal from the final solution.

For an initial volume V0 of unknown and added volume Vs of standard with concentration [S]i ,

The total volume is

V=V0+Vs

And the concentration of equation 1 can be written as

[X]f=[X]i(V0V)[S]f=[S]i(VSV)

(a)

Expert Solution
Check Mark

Answer to Problem 5.23P

The expression for the final concentration [Cu2+]f after dilution was expressed as 0.950[Cu2+]i

Explanation of Solution

Given,

An unknown sample of Cu2+ gave an absorbance of 0.262.  1.00mL Of a solution had 100.0ppm Cu2+ and the mixture is diluted to 100.0 in a volumetric flask. The new solution absorbance was 0.500

[X]f=[X]i(V0V)

[Cu2+]f=[Cu2+]i(ViVf)=0.950[Cu2+]i

Conclusion

An expression for the final concentration [Cu2+]f after dilution was expressed.

(b)

Interpretation Introduction

Interpretation:

An expression for the final concentration of standard Cu2+designatedas[S]f after dilution has to be expressed.

Concept Introduction:

Standard addition,

Standard addition are the addition of known quantities of analyte to unknown solution, with the increase in linearity we can deduce that how much analyte present in the original unknown solution.

Standardadditionequation=[X]i[S]f+[X]f=IXIS+X...(1)

Where,

[X]i = The concentration of analyte in initial solution.

[S]f+[X]f = The concentration of analyte plus standard in final solution.

IX = Signal from the initial solution

IS+X =signal from the final solution.

For an initial volume V0 of unknown and added volume Vs of standard with concentration [S]i ,

The total volume is

V=V0+Vs

And the concentration of equation 1 can be written as

[X]f=[X]i(V0V)[S]f=[S]i(VSV)

(b)

Expert Solution
Check Mark

Answer to Problem 5.23P

The expression for the final concentration of standard Cu2+designatedas[S]f after dilution was expressed as 1.00ppm

Explanation of Solution

Given,

An unknown sample of Cu2+ gave an absorbance of 0.262. 1.00mL Of a solution had 100ppm Cu2+ was mixed with 95.0mL of unknown and the mixture is diluted to 100.0 in a volumetric flask. The new solution absorbance was 0.500

[S]f=[S]i(ViVf) = (100.0ppm)(1.00mL100.0mL)=1.00ppm

Conclusion

An expression for the final concentration of standard Cu2+designatedas[S]f after dilution was expressed.

(c)

Interpretation Introduction

Interpretation:

The concentration of [Cu2+]i in the unknown has to be calculated.

Concept Introduction:

Standard addition,

Standard addition are the addition of known quantities of analyte to unknown solution, with the increase in linearity we can deduce that how much analyte present in the original unknown solution.

Standardadditionequation=[X]i[S]f+[X]f=IXIS+X...(1)

Where,

[X]i = The concentration of analyte in initial solution.

[S]f+[X]f = The concentration of analyte plus standard in final solution.

IX = Signal from the initial solution

IS+X =signal from the final solution.

For an initial volume V0 of unknown and added volume Vs of standard with concentration [S]i ,

The total volume is

V=V0+Vs

And the concentration of equation 1 can be written as

[X]f=[X]i(V0V)[S]f=[S]i(VSV)

(c)

Expert Solution
Check Mark

Answer to Problem 5.23P

The concentration of [Cu2+]i in the unknown was calculated as 1.04ppm .

Explanation of Solution

Given,

An unknown sample of Cu2+ gave an absorbance of 0.262.  1.00mL Of a solution had 100ppm Cu2+ was mixed with 95.0mL of unknown and the mixture is diluted to 100.0 in a volumetric flask. The new solution absorbance was 0.500

Standardadditionequation=[X]i[S]f+[X]f=IXIS+X

[Cu2+]i1.00 ppm +0.950[Cu2+]i=0.2620.500=1.04ppm

Conclusion

The concentration of [Cu2+]i in the unknown was calculated.

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